The fluorenone is more polar because it belongs to the ketone family. The fluorene is an aromatic molecule without polar fonction and this is not the case of the fluorenone, it contains a carbonyl fonction (carbon-double bond-oxygen).
Well it depends on the solvent you are using, but lets assume you use pentane as the solvent for fluorene and diethyl ether as the solvent for fluorenone. Used in this order, fluorene should actaully move slower down the column due to the the polarity of the alumina and the nonpolarity of the solvent (pentane). Since fluorene is less polar so, remember the rule like dissolves like? Well, this kind of applies to chromatography wherein rather than dissolve just replace it with moves with, so like moves with like. That being said the pentane will "carry" the fluorene through the alumina slower than the latter (which I will explain). Fluorenone is polar because of its C=O bond, that being said the dielectric constant of diethyl ether is 4.3 which means it has intermediate polarity (remember that pentane has a dielectric constant of 2.1 I think, so it is nonpolar). Since the alumina, diethyl ether, and the fluorenone are all polar, the fluorenone will travel faster through the alumina than would the fluorene, because there is no attraction between all these polar compounds which will allow it to move faster, rather than a nonpolar and polar chemical having an attration towards each other and thus moving more slowly. Hope this helps, Branden
To separate fluorene from toluic acid, one can oxidize the fluorene to fluorene in air by dissolving the mixture in a mix of toluene and strong sodium hydroxide. By adding a phase transfer catalyst like Aliquat, the two components can be separated.
Water is a polar molecule, polar molecules are more soluble in other polar molecules. Oxygen helps make organic molecules more polar, and therefore more soluble in water.
yes, because Cl is more polar then C
Yes , phenol is more polar than toluene. because ph-OH has more dipole moment than Ph-CH3
Well it depends on the solvent you are using, but lets assume you use pentane as the solvent for fluorene and diethyl ether as the solvent for fluorenone. Used in this order, fluorene should actaully move slower down the column due to the the polarity of the alumina and the nonpolarity of the solvent (pentane). Since fluorene is less polar so, remember the rule like dissolves like? Well, this kind of applies to chromatography wherein rather than dissolve just replace it with moves with, so like moves with like. That being said the pentane will "carry" the fluorene through the alumina slower than the latter (which I will explain). Fluorenone is polar because of its C=O bond, that being said the dielectric constant of diethyl ether is 4.3 which means it has intermediate polarity (remember that pentane has a dielectric constant of 2.1 I think, so it is nonpolar). Since the alumina, diethyl ether, and the fluorenone are all polar, the fluorenone will travel faster through the alumina than would the fluorene, because there is no attraction between all these polar compounds which will allow it to move faster, rather than a nonpolar and polar chemical having an attration towards each other and thus moving more slowly. Hope this helps, Branden
Not soluble in water
C13H10
What does fluorine conduct
Marlyn Homer Bortner has written: 'The crystal structure and molecular structure of fluorene' -- subject(s): Fluorene
Which is more polar acetonitrile or methnol?
Non-polar molecules are more attracted to other non-polar molecules.
I'm not positive about the correct mechanism, but I can propose one that seems plausible. Oxygen can exist as a singlet or triplet species. The triplet species (O-O with 2 lone pairs and a radical on each O) is the ground state species, so unless O2 is excited, it will most likely react in this manner. Using that assumption, O2 can abstract a proton radical from flourene to form a fluorene radical (with the radical at the benzylic position). This is the initiation of a radical chain process. Next, the peroxy radical can attach to the fluorene radical (thus terminating the chain). Alternatively, another O2 molecule can attach to the fluorene radical. This peroxy fluroene radical can abstract a proton from a fluorene molecule, propogating a fluorene radical. In either case, the resulting species is a peroxy fluorene molecule. Now, you can draw a mechanism where a hydroxide anion (the reaction is run in base) pulls off the remaining benzylic proton, pushing electrons into a carbon to oxygen pi bond, and breaking the oxygen-oxygen single bond to release hydroxide. As I said, I have no evidence for this mechanism, just using my chemical knowledge and experience.
CCl4 is not polar. But CHCl3 is polar.
Fluorenone is more polar than ferrocene.Ferrocene is non-polar due to its symmetry.
To separate fluorene from toluic acid, one can oxidize the fluorene to fluorene in air by dissolving the mixture in a mix of toluene and strong sodium hydroxide. By adding a phase transfer catalyst like Aliquat, the two components can be separated.
CH3OH is more polar the others have more hydrocarbons on the them making them less polar and less soluble.