The reaction presumably is Cl2 + 2 KBr = 2KCl + Br2. The potassium chloride (KCl) is a salt.
2KBrO3 --> 2KBr + 3O2 What gas product is produced is the right question. Oxygen gas.
The chemical name for the product of reaction betweenpotassium and fluorine is potassium fluoride.
Reaction scheme of vanillin with potassium permanganate to vanillic acid...:)
NaCl or sodium chloride.
The products are Potassium bromide(KBr), Water(H2O) and Carbon(CO2). KHCO3 + HBr ----> KBr + H2O + CO2
Potassium chloride
It is lead bromide and potassium nitrate
Yes. The formula for potassium chloride is KCl, showing that equal numbers of atoms of potassium and chlorine are required to form the compound. The gram atomic masses of these two atoms are close enough that the given amounts of the two elements show far more than enough chlorine to complete the reaction. Therefore, the only product of the reaction will be potassium chloride, but there will be a considerable amount of unreacted chlorine remaining after the reaction is complete.
2KBrO3 --> 2KBr + 3O2 What gas product is produced is the right question. Oxygen gas.
The reaction is 2K + F2--> 2KF The product is potassium fluoride
The product of the synthesis reaction between sodium and chlorine gas is
The product of this reaction is magnesium bromide which is a salt.
When a substance is aqueous, it means that it is dissolved in water. In aqueous reactions, the reaction is always a double replacement reaction, meaning one ion of a compound will switch with an ion from the other compound. A precipitate is an substance that is not soluble in water, meaning it cannot be dissolved. You can tell whether or not a substance is precipitate using a solubility chart. Therefore, using a solubility chart, we can tell that the product silver bromide will be the precipitate and the product potassium nitrate will be aqueous.
ethyl nitrite
CaCl2
The chemical name for the product of reaction betweenpotassium and fluorine is potassium fluoride.
Reaction scheme of vanillin with potassium permanganate to vanillic acid...:)