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Why do you say the oxidation number of zinc in zinc carbonate is 2?
Wiki User
∙ 10y ago
The molecular formula for Zinc Carbonate is ZnCO3.
Knowing that the Carbonate anion has an oxidation charge of -2, then in order to balance that negative charge with only ONE zinc atom, zinc must be caring a +2 oxidation number.
So yes, you are correct.
In general, you simply have to write down the algebraic equation:
(Ncation)(Ocation) + (Nanion)(Oanion) = 0
where N is the number of ionic units and O is the oxidation number.
In this case you'd have:
(1)(Ocation) + (1)(-2) = 0
(Ocation) - 2 = 0
(Ocation) = 2
Wiki User
∙ 10y ago
Wiki User
∙ 12y agoDr M Kanagasabapathy
Asst. Professor, Department of Chemistry
Rajus College, Affiliated to M K university
Rajapalayam (TN) India PIN 626 117
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Answer
Zinc is the cation and has the valency two. And carbonate anion also has the valency two.
So the formula ZnCO3.
In ionic forms Zn2+ and CO32-.
Zinc carbonate is formed by the reaction with zinc hydroxide or Zinc metal with carbonic acide.
Carbonic acid is nothing but carbon di oxide gas dissolved in water. (Soft drink beverages)
Zn + H2CO3 = ZnCO3 + H2
Zinc carbonate is different from zinc bi carbonate Zn(HCO3)2
By
Dr M Kanagasabapathy
Asst. Professor, Department of Chemistry
Rajus College, Affiliated to M K university
Rajapalayam (TN) India PIN 626 117
Wiki User
∙ 11y ago+2 for zinc
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Is zinc molecular?
It would be more correct to say that Zinc is an element
What is the product when 3 octanol undergoes oxidation?
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Is zinc sulfate available in liquid form?
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i would say maybe aluminum, copper, bronze, zinc and tin.
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Impossible to say without knowing what the mixture is.
What is the oxidation number of Mn?
Lets say the oxidation number of Mn is x oxygen's oxidation number is -2 and the charge on the molecule is 1- so: 1(x) + 4(-2) = 0 x - 8 = 0 x = +8 and then you must remember that there is a negative charge to the molecule. Subtract 1. therefore oxidation number on Mn is +7
What' is oxidation number?
'Oxidation number' and oxidation state are often used interchangeably. Oxidation state is a formal way of determining the degree of oxidation of an atom or ion or molecule; for ions the oxidation number is equal to the ionic charge. In non ionic compounds the most electronegative element is assumed to "own" the electrons. So in say InP which is a semiconductor and not ionic, the oxidation state of indium is +III and P is -III. Oxidation number is a convention used in complexes. Ligands are removed from the ion with all bonding electrons. Often the oxidation number and oxidation state have the same values but calculating the the oxidation number of N in ammonia, H is removed as hydride ion, H- you get the strange looking result of nitrogen with an oxidation number of +3. In contrast the oxidation states of N and H would be calculated as -III and +1
What oxidation number?
'Oxidation number' and oxidation state are often used interchangeably. Oxidation state is a formal way of determining the degree of oxidation of an atom or ion or molecule; for ions the oxidation number is equal to the ionic charge. In non ionic compounds the most electronegative element is assumed to "own" the electrons. So in say InP which is a semiconductor and not ionic, the oxidation state of indium is +III and P is -III. Oxidation number is a convention used in complexes. Ligands are removed from the ion with all bonding electrons. Often the oxidation number and oxidation state have the same values but calculating the the oxidation number of N in ammonia, H is removed as hydride ion, H- you get the strange looking result of nitrogen with an oxidation number of +3. In contrast the oxidation states of N and H would be calculated as -III and +1
Is zinc molecular?
It would be more correct to say that Zinc is an element
What is the oxidation state of boron in the peroxoborate ion?
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What is the oxidation number of sulfur in s2o3 2-?
+6. Working this out is tricky. Not knowing the structure, and assuming each oxygen was present as O2- you would have to say -7. This is difficult to understand as S has only 6 valence electrons. The structure is actually O3SOOSO3,(see link), 6 oxide ions (oxidation number -2) and 1 peroxide ion (overall oxidation number -2, average oxygen oxidation number of -1) . Overall the oxygen atoms contribute -14, and less the charge on the ion of -2 gives the total oxidation number of both sulfur atoms as +12, so each sulfur is +6. This is a lot more sensible. S has its maximum oxidation number of +6 as it does in SO3 and SO42-.
How do you solve for the oxidation number of a chlorate ion?
The chlorate ion is ClO3-. Some text books say that the oxidation number of the whole ion is equal to the charge, so in this cas it would be -1. However most teachers would sya that oxidation numbers only refer to atoms. So working out the oxidation numbers:- oxygen is -2, (using the rule, or if you use the he electronegativity method- gives the same answer as O is more electronegatoive than Cl) the sum of oxidation numbers of Cl and O are -1 (the charge on the ion) - I'll call the oxidation number of Cl OxCl -1 =OxCl + (3* -2)= OxCl -6 therefore OxCl = +5
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I have no idea....just wanted to say hi!
What is the ionic name of ZnCrO4?
Well you've got Zinc, Chrome and 4 Oxygen atoms in there so i would say.... Zinc Chromate
What is the product when 3 octanol undergoes oxidation?
Impossible to say without more detail. Oxidation includes burning to give CO2 and H2O
How can you tell an elements oxidation number by looking at the periodic table?
1. Elements on their own have an oxidation # equal to 0. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, Ca and 2Ag would have oxidation #s equal to 0.) 2. Ions in ionic compounds have an oxidation # equal to their charge. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, 2AgCl = Ag+1 and Cl-1, and CaCl2 = Ca+2 and Cl2-1.)
