I never measured the resistance of an electric iron, but: the 15 ohm resistance is probably required to develop a required 806 watts of power. Using Ohm's law, I(current) = E(voltage)/R(resistance), therefore
I(current) =110 volts/15 ohms = 7.33 Amps (current), and, Power (watts) = E(voltage) X I(current); 110 volts X 7.33 amps = 806 watts. The iron requires that wattage to develop enough heat in the sole of the iron. Hope this helps.
I can't do all the math for that but if it helps that's a 1,077.3 watt heat discharge.
That depends how they are connected. For example, if they are connected in series, just add the individual resistances.
15 to 40 ohms.
V=I*R Where: V is voltage I is the current in ampers R is resistance in ohms. So, if the current is 15 A and the resistance is 5 ohms, then the voltage must be 15 A *5 ohms = 75 V.
E= ( I ) x ( R ) = (15 amperes) x (4 ohms) = 60 voltsNote:When 15 amperes flows through a resistance of 4 ohms,the resistance dissipates 900 watts. If it is not part of atoaster or a blow drier, it either melts or explodes.
I can't do all the math for that but if it helps that's a 1,077.3 watt heat discharge.
That depends how they are connected. For example, if they are connected in series, just add the individual resistances.
Ohms law states that E=I * R, or voltage equals current times resistance. Therefore current equals voltage divided by resistance. 120v divided by 16 ohms equals 7.5 amps.
15 to 40 ohms.
If we use the simple application of Ohm's law where voltage (E) equals current (I) times resistance (R), or E = I x R, all we need to do is plug in values. If E = I x R and I = 8 amps and R = 15 ohms, E = 8 x 15 = 120 volts.
Here is what I go by, 0 - 15" min 3000 ohms, max 10000 ohms. 15 - 25" min 4000 ohms, max 15000 ohms. 25 - 35" min 6000 ohms, max 20000 ohms. Over 35" min 8000 ohms, max 25000 ohms.
Ohm's Law Voltage = Current x Resistance Answer is 15/300
V=I*R Where: V is voltage I is the current in ampers R is resistance in ohms. So, if the current is 15 A and the resistance is 5 ohms, then the voltage must be 15 A *5 ohms = 75 V.
E= ( I ) x ( R ) = (15 amperes) x (4 ohms) = 60 voltsNote:When 15 amperes flows through a resistance of 4 ohms,the resistance dissipates 900 watts. If it is not part of atoaster or a blow drier, it either melts or explodes.
10 - 15 K ohms per foot
15 k ohms with a 10% tolerance.
You don't need the voltage to calculate that. Just use the product-over-sum formula (for two resistors): R = (R1 x R2)/(R1 + R2) Where R is the equivalent resistance, and R1 and R2 are the individual resistances.