Electron configuration for N (at. no. 7) is 1s2 2s2 2p3 so the 2p orbital, which can hold 6 electrons, is only half full. Is that what you are asking?
Looking at the electron configuration of carbon (at. no. 6) you have 1s2 2s2 2p2. In the 2 p subshell, you have 1 electron in the 2px orbital, and 1 electron in the 2py orbital and no electrons in the 2pz orbital. So, the answer is that there are TWO half filled orbitals in the carbon atom. This is the case BEFORE hybridization. After hybridization, there are FOUR half filled orbitals which are called sp3 hybrids.
The electron affinity, or EA, of nitrogen is less than zero (EA = -7) because of is electron configuration, which is [He] 2s2 2p3. Nitrogen, as a neutral atom has a half-filled p-orbital, and by Hund's Rule, that means that each p-orbital has 1 unpaired electron. In the same way that a completely filled orbital is especially stable (like the noble gases), a half-filled orbital IN A NITROGEN ATOM IS HIGHLY UNSTABLE ([He] 2s2 2p4).In contrast, carbon, C, has a much larger electron affinity (EA = -123.4 kJ/mol) because it has electron configuration [He] 2s2 2p2, which means that the addition of one more electron will bring it to an extra stable half-filled shell. Fluorine of course has an extremely high electron affinity (EA = -331.4 kJ/mol) because of it's electron configuration, [He] 2s2 2p5, where the addition of one more electron gives it a completely filled valence shell or noble gas configuration, [He] 2s2 sp6.
When less than half of the outer energy level is filled!
carbon. though nitrogen is more electronegative than carbon but carbon has more affinity for electrons as nitrogen has half filled stability...
The electronic configuration of atoms is based on the filling of orbitals. In the case of the 4s orbital, it is relatively lower in energy than the 3d orbital, so it is filled first. Therefore, the 4s orbital can accommodate a maximum of 2 electrons. As for the 3d orbitals, they have a higher energy level and can accommodate a maximum of 10 electrons, but in the case of transition metals, only 5 electrons fill the 3d orbitals due to electron configuration stability.
Looking at the electron configuration of carbon (at. no. 6) you have 1s2 2s2 2p2. In the 2 p subshell, you have 1 electron in the 2px orbital, and 1 electron in the 2py orbital and no electrons in the 2pz orbital. So, the answer is that there are TWO half filled orbitals in the carbon atom. This is the case BEFORE hybridization. After hybridization, there are FOUR half filled orbitals which are called sp3 hybrids.
The electron affinity, or EA, of nitrogen is less than zero (EA = -7) because of is electron configuration, which is [He] 2s2 2p3. Nitrogen, as a neutral atom has a half-filled p-orbital, and by Hund's Rule, that means that each p-orbital has 1 unpaired electron. In the same way that a completely filled orbital is especially stable (like the noble gases), a half-filled orbital IN A NITROGEN ATOM IS HIGHLY UNSTABLE ([He] 2s2 2p4).In contrast, carbon, C, has a much larger electron affinity (EA = -123.4 kJ/mol) because it has electron configuration [He] 2s2 2p2, which means that the addition of one more electron will bring it to an extra stable half-filled shell. Fluorine of course has an extremely high electron affinity (EA = -331.4 kJ/mol) because of it's electron configuration, [He] 2s2 2p5, where the addition of one more electron gives it a completely filled valence shell or noble gas configuration, [He] 2s2 sp6.
This is because in nitrogen the 2p subshells are filled by 3 electrons which is half filled electronic configuration. But oxygen has to lose an electron to attain the half filled electronic electronic configuration. Hence nitrogen is more stable than oxygen.
When less than half of the outer energy level is filled!
No but your mom does
nitrogen has higher ie than oxygen because of thd half filled p-orbital ie. 1s2 2s2 2p6 hence more enery is required to remove the electron from the orbital nitrogen has more ie than carbon because as we move along a period the ie increase becausean.electron is added to the valence shell
An electrically charged atom or group of atoms with an unpaired electron in its outermost shell is called a free radical. If the outermost shell of an atom is half-filled with electrons, that atom is most likely to share electrons.
no. they are more stable when they have completely filled or half filled shells
carbon. though nitrogen is more electronegative than carbon but carbon has more affinity for electrons as nitrogen has half filled stability...
because he cant
Chromium has a half filled D orbital so is stable.
There's two ways to answer this question. First electron configurations with half-filled sublevels are more stable then electron configurations that don't have half-filled sublevels. Since Selenium is one elctron away from achieving a more stable half-filled sublevel configuration it more readily gives up it's outermost electron, so less energy is requires to remove the outermost electron. Arsenic already has the stable configuration of half-filled sublevel so it wouldn't give up it's electron as readily, so more energy is required to remove it. Another way to look at it is that Selenium's outermost electron is in a p orbital that already has an electron so there is electron electron repulsion present in that orbital so it's attraction to the nucleus is less which is why less energy is required to remove it so the ionization energy is less. Arsenic has it's outermost electron unpaired in the p orbital so there is no electron electron repulsion present in that orbital so more energy is required to remove it then for Selenium's outer most electron. Hope this helps!