... in CE configure...
as Vo=Vcc-Ic Rc now as Vcc is consistent. v can say Vo is directly proportional 2 (-Ic Rc) so now when the base voltage is increased Ib will inc. thus, Ic will inc. cuz Ic=beta Ib thus Ic Rc drop increases... as Vo is prop 2 -Ic Rc thus, Vo will decrease...thus d curve for d +ve half cycle in which Ib is increasing drawn in 180 deg phase showing Vo is dec. n vice versa 4 -ve half cycle...
now in CC...
as d o/p is taken from emitter... Vo= Ie Re so der's no -ve sign..n for d +ve cycle Ie will increase leakage current) as der's no-ve sign it'll b in phase wid i/p..hence no phase shift as leakage current doesn't increase so much thus, dis o/p voltage Ie Re doesnt inc much thus, d o/p doesn't amplify much thus dis configure known as emiter follower...
now in CB,...
d I/P is applied at emitter n o/p is taken from collector... so, 4 d +ve half cycle d Eb junc will b more FB thus causing incr. in Ib n thus, in Ic... so inc. in Ic causes inc. in o/p voltage..n during -ve half cycle d junc will b less FB so o/p voltage will b decreasing..hence der's no phase shift...
phase shift in integrator is 180 degrees and phase shift in differentiator is 0 degrees
single phase variac can give 0-270 voltage in ac forms. So it is used to know the voltage in any circuit.
'A' and 'C' are saying exactly the same thing. The correct choice is 'D'. The complex impedance of a purely resistive circuit is purely real. Since there is no reactance, there is no phase shift, so the power factor is ' 1 ', KVA = KW, KVAR = 0, etc.
Shift registers contain multiple "flip flops" that can be set to represent a bit value (0 or 1). These values can be retrieved later and so the registers can function as memory.
A: it must apply to AC since there is no phase in DC. Since AC is a complete circle 0-360 degrees the principle if to conduct current at a degree of the circle. And AC has both positive 0 to 180 and negative 180 to 360 polarity it is possible to control output power by conducting current only at certain angle of the circle . The phase angle is to differentiate the conducting current in which quadrant of the circle
phase shift in integrator is 180 degrees and phase shift in differentiator is 0 degrees
Y=12sin(x(pi)) amplitude= 12 period = 2 phase shift = none or 0 vertical shift = none or 0
An analog phase shifter provides a phase shift with a varying control voltage. A digital phase shifter switches among phase states to provide discrete phase shifts. the more bits there are, the smaller the quantization/digitization error. For example, 1 bit phase shifter provides a phase shift of 0 and 180°, or 0 and 90°. 2 bit phase shifter provides a phase shift of 0, 90°, 180° and 270°. 3 bit phase shifter provides a phase shift of 0, 45°, 90°, 135°, 180°, 225°, 270°, 315°, 360°.
If there are only a resistor and a capacitor in the circuit, then the phase shift will indeed be between 0 and 90 degrees. When the resistor and capacitor are in series, the phase shift will be negative when the capacitor is connected to a source voltage and the resistor is the load. The phase shift will be positive when the resistor is connected to the source. The lower the values of R and C, the higher the frequency bandwidth.With the resistor and capacitor connected in series and the two parts connected to a current source, the phase shift will be negative. At high frequencies, the output voltages is lower, and the circuit appears as a very low impedance. At low frequencies, the circuit looks more like a resistor. Again, the phase shift will be between 0 and 90 degrees.CommentThe correct term is phase angle, not 'phase shift'. By definition, the phase angle is the angle by which the load current leads or lags the supply voltage. For an RC circuit, the current leads the voltage, so the phase angle is a leading phase angle.
phaseshift of wienbridge is 0
0 C. B. with A.
We start with an empty stack and with a complete S$ sentence on input ... We call this a state: state 0, the start state with an empty prefix (V[ε]). CS453. Shift-reduce Parsing. 3. Page 4. Shift, reduce, goto actions in LR(0) table construction ... Build an SLR parser for our expression grammar. 0: .
Numbers quantity in each jar in 19 - 13 - 7 order. 0 13 7 7 13 0 19 1 0 12 1 7 12 8 0 5 8 7 5 13 2 18 0 2 18 2 0 11 2 7 11 9 0 4 9 7 4 13 3 17 0 3 17 3 0 10 3 7 10 10 0 .......for example assume jar A,B,C: switch over like this CA BA AC CB AC CB CB BA CB AC CB AC CB BA CB AC CB
When the ring, R, is an integral domain. That is, when R has no zero divisors. Consider: ab=cb => ab-cb=0 => (a-c)b=0 Then because R has no zero divisors we have: a-c=0 => a=c
The graph of y = A sin (Bx + C) is obtained by horizontally shifting the graph of y = A sin Bx, where 1) Amplitude = |A|, the maximum of y is A, if A > 0 and -(-A) if A < 0 The minimum of y is -A if A > 0 and A if A < 0 2) Period = (2pi)/B 3)Phase shift = C/B So that the starting point of the cycle is shifted from x = 0 to x = C/B. If C/B > 0 the shift is to the right. If C/B < 0 the shift is to the left.
shift+9 shift+0
In abs. PSK only instant phase for the incoming bits are considered. For DPSK, the difference between previous phase and the present phase is considered. Example: If BPSK is used, then for 0 if phase if pi and for 1 it is 0, then for abs. BPSK the phase states for the bit stream 1010 will be 0,pi,0,pi for DPSK, we assume initial phase is zero and a rule that , if incoming bit is zero, then phase difference is 0 and if it is 1 then, phase difference is pi. So, phase difference will be--pi,0,pi,0 Instant phase will be, pi,pi,0,0....Easy!!