Because it just IS and due to fullfield electron configuration that make noble gas more stable. so neon has more ie.
The energy to remove 1 electron is the first ionization energy. To remove a second electron requires more energy. This is because the electron being removed now has to overcome the +1 positive charge introduced after the 1st electron was removed.
Sodium has only one valence electron, and when that is donated to some other atom, the remaining ion has a noble gas configuration that is highly stable. Disrupting that by another ionization requires much energy. Magnesium has two valence electrons; therefore the second is almost as easy to donate as the first. The third ionization enthalpy of magnesium would be very high.
Across a period, first ionization energy increases. However, when going down a group, first ionization energy generally decreases. As you go down a group, atoms hove more total electrons so they don't really care that much about their outermost ones.
Ionization energies generally become larger as electrons are removed from an atom since it becomes harder and harder to remove the next electron. Ionization energies increase from left to right across the periodic table and decrease as you go down the periods. Ionization will decrease sharply when an electron is removed from an atom and results in the cation obtaining a full outer shell. For example: In the element calcium the 2nd ionization energy is greater than the second ionization energy. You can think of it this way. When you remove an electron, the nucleus is able to better hold onto the remaining electrons of the positive ion so the removing the second electron is more difficult. In calcium the 3rd ionization energy is much larger than the second. This is because the 3rd electron is being removed from the 2nd energy level instead of the 3rd energy level. The second energy level is closer to the nucleus than the third so the nucleus is even more effective at holding onto the electrons.
It has something to do with the effective nuclear charge experienced by the valence electrons in Al and Ga. While aluminum's valence electrons are in the 3p shell, and there are 13 protons in the nucleus. Gallium's valence electrons are in the 4p shell, and there are 31 protons in the nucleus. Additionally, the atomic radius of gallium is not too much larger than that of aluminum. Thus, the electrons in gallium are pulled more strongly to the nucleus and they are more difficult to remove. A similar but lesser effect can also be seen in group IV/14, where Germanium has an almost identical first ionization energy to Silicon, and after the F shell is filled--thallium has a higher first ionization energy than Indium, and Lead has a higher first ionization energy than tin.
The energy to remove 1 electron is the first ionization energy. To remove a second electron requires more energy. This is because the electron being removed now has to overcome the +1 positive charge introduced after the 1st electron was removed.
The second ionization energy of sodium is so much greater than the first because the first electron is removed from the valence shell, while the second electron is removed from the core orbitals. Additionally, the sodium atom has a positive charge after the first ionization, which thus attracts the remaining electrons more strongly. Both of these factors lead to a much higher second ionization energy compared to the first.
the 1st ionization energy is 403.03 kJ/mol.. since it's oxidation state is +1, you don't normally take away more than one electron so the 2nd and 3rd ionization energies are much larger and don't usually matter
In general, the larger the atom the lower the first ionization energy at the right hand side of the periodic table. Take Lithium and Francium as examples. With Francium, the outer electron is much further away from the attractive power of the nucleus and is shielded by all the other electrons. The attraction is lower and thus it is easier to remove the electron making the first ionization energy lower. Incidentally, it makes it more reactive.
Sodium has only one valence electron, and when that is donated to some other atom, the remaining ion has a noble gas configuration that is highly stable. Disrupting that by another ionization requires much energy. Magnesium has two valence electrons; therefore the second is almost as easy to donate as the first. The third ionization enthalpy of magnesium would be very high.
Caesium's single outer electron is much further from the nucleus than that of sodium, so caesium loses its valence electron much easily than sodium, therefore caseium is much more reactive than sodium.
This is called the ionization energy and an is different for each electron in the atom. Electrons in the outer shell (furthest from the nucleus) have the lowest ionization energy, electrons in the innermost shell (closest to the nucleus) have the highest ionization energy.
Across a period, first ionization energy increases. However, when going down a group, first ionization energy generally decreases. As you go down a group, atoms hove more total electrons so they don't really care that much about their outermost ones.
Ionization energy represents the energy required to remove electrons from an atom. The first and second ionization energies are relatively small because the lectrons must be removed from the 2s orbital. For the third ionization energy the electron must be removed from the 1s orbital which has less energy than the 2s, and so requires much more energy to be removed.
The relationship between atomic numbers and first ionization energies is that within the same period, as atomic number increases so does first ionization because as nuclear charge increases and atomic radius decreases, electrons become harder to remove. However, within the same group, the first ionization energy decreases as atomic number increases because of the added energy level, the electrons are farther from the nucleus and easier to remove.
The first ionization energy is the energy that is required in order to remove the first electron from an atom in the GAS phase, the second ionization energy is the energy required to remove the second electron from an atom in the GAS phase. Ionization energy will generally increase for every electron that is removed and increases from left to right in the periodic table and moving up the periods.
Imagine that one electron has already been removed from an atom, the energy used to accomplish this is the 1st ionization energy. Now more energy is needed to remove a 2nd electron. That is the 2nd ionization energy.