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g HCl solution = 2500 mL of HCl * 1 liter/1000 mL * 1190 g/L = 2975 g

37% solution (37 g HCl/100 grams of solution) gives you the grams of HCl:

g HCl = 0.37 * 2975 g = 1100.8 g HCl

Moles HCl = 1100.8/(36.46 g/mole) = 30.2 moles

Therefore the molarity, which equals the normality in this case = 30.2 moles/2.5 L = 12.07 M = 12.07 N

If you want to make 100 mL of a 0.1 N solution,

Volume of HCl solution needed = (0.1 N * 100 mL) /12.07 N = 0.83 mL

Take 0.83 mL of the 37% HCl, and dilute it with water to 100 mL.

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Q: Why standard normality of HCl is 11.3 N?
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What is the normality of commercial grade HCl?

The normality of commercial grade hydrochloric acid (HCl) can vary depending on the concentration specified by the manufacturer. Hydrochloric acid is commonly available in different concentrations, such as 37% or concentrated hydrochloric acid. To determine the normality, it is essential to know the molarity (moles of solute per liter of solution) and the number of equivalents of the acid. Normality (N) is related to molarity (M) by the equation: � = � × � N=n×M where: � N is the normality, � n is the number of equivalents, � M is the molarity. For hydrochloric acid (HCl), which is a monoprotic acid (donates one proton), the number of equivalents ( � n) is equal to 1. Therefore, if you know the molarity of the commercial grade hydrochloric acid, you can determine its normality using the equation mentioned above. It's important to check the product label or contact the manufacturer for the specific concentration of the hydrochloric acid you are using.


How many ml of 6.0 N NaOH is required to neutralize 30 ml of 4 N HCL?

formula for neutralizatrion is volume of acid X normality of acid = volume of base X normality of base so (0.3)(3) should equal (4)(volume) which is .225L. However, Ca(OH)2 contains 2 moles of OH resulting division of total volume needed by 2. Thus, the answer becomes .1125L or 112.5ml.


Prepare 500ml of 0.12N HCL solution?

add 5 ml of 37% HCl to 495 ml Water. This is 0.12 N ;)


Equation used to determine the iodine value?

Iodine value= (B-S)N x 12.69 ------------------- wt of sample where, B=titration of blank S= titration of sample N= normality of thiosulphate


Difference in the solubality of ciprofloxacin in water and 0.1N HCl solution i-e. I mean to ask that either in water or 0.1 N HCl solution the ciprofloxacin is more soluble?

the solubility of ciprofloxacin in water is 0.35g/10ml ,and in 0.1N Hcl is about 0.25g/10ml that means solubility of ciprofloxacin in water is more when compared to 0.1N Hcl

Related questions

What is the normality of commercial grade HCl?

The normality of commercial grade hydrochloric acid (HCl) can vary depending on the concentration specified by the manufacturer. Hydrochloric acid is commonly available in different concentrations, such as 37% or concentrated hydrochloric acid. To determine the normality, it is essential to know the molarity (moles of solute per liter of solution) and the number of equivalents of the acid. Normality (N) is related to molarity (M) by the equation: � = � × � N=n×M where: � N is the normality, � n is the number of equivalents, � M is the molarity. For hydrochloric acid (HCl), which is a monoprotic acid (donates one proton), the number of equivalents ( � n) is equal to 1. Therefore, if you know the molarity of the commercial grade hydrochloric acid, you can determine its normality using the equation mentioned above. It's important to check the product label or contact the manufacturer for the specific concentration of the hydrochloric acid you are using.


How to prepare 0.2N HCl solution?

0.2 N HCl solution means 0.2 equivalents of HCl dissolved in 1 litre of water. Normality = Molarity x n-factor => Molarity =Normality/n-factor=0.2/1=0.2 M 0.2 moles should be present in 1 litre of solution. 0.2moles =0.2 x 36.5 = 7.3 grams of HCl =>Dissolve 7.3 grams of HCl in 1 litre if water to get a 0.2N solution.


What is the normality of one liter solution if it has 3.65 grams of Hydrochloric acid?

Normality is the number of gram equivalents of solute per liter of solution.N = [ ( m ) / ( M ) ( Z ) ] [ 1000 / V in mL ]where Z represents the number of H+ ions that the one molecule of the solute is capableof releasing or reacting with. For HCl, Z = 1 .N = [ ( 3.65 g ) / ( 36.458 g / mol ) ( 1 ) ] [ 1000 mL / 1000 mL )N = 0.100 N


How many ml of 6.0 N NaOH is required to neutralize 30 ml of 4 N HCL?

formula for neutralizatrion is volume of acid X normality of acid = volume of base X normality of base so (0.3)(3) should equal (4)(volume) which is .225L. However, Ca(OH)2 contains 2 moles of OH resulting division of total volume needed by 2. Thus, the answer becomes .1125L or 112.5ml.


What is the normality of a 6.35 M H2SO4 is?

0.08 n


What volume of 1.25M HCl would be required to prepare 180mL of a 0.500M HCl solution?

The answer is 15,039 g hydrogen chloride (HCl).


What does the N stand for in 0.02 N acid?

The N of 0.02 N acid stands for the "normality". The normality is defined as the gram equivalent weight of a substance in a liter of solution. so, a 0.02 acid would have 0.02 gram equivalents of acid per liter. In short N means "normality" and stands for "g/l"


What is the normality of a 1.25 M solution of H2SO4?

Sulfuric acid H2SO4 will give away 2 protons H+ for this reason its normality is 2 times its molarity. so for H2SO4 M = 2N For HCl M= 1N because HCl has only one proton H+ H3PO4 for example has 3N = M so for your case, 6M = 2N and N= 6/2 = 3.


What is the unit of normality?

The unit for normality is N, or mol/LN or mol/Lit is the unit


What is the normality if 25mL of 0.5 N NaOH is needed to neuralize 30 mL of the unknown acid solution?

25 (mL) * 0.5 (N) = 30 (mL) * X (N) X = unknown normality of acid = (0.417 N) = 0.4 N


What is pH of 0.1 N HCL?

0.1 M HCl =============


How do you prepare a 1N HCl solution?

dilute 85ml of HCL to 1000ml This answer does not state which is the original concentration of the 85ml of HCL mentioned. The question should state what does the operator have initially (for example "I have HCl 87.5% (v/v; 7+1) solution and I want to get 1N solution of HCl, what should I do?"