Insufficient data. Current drawn depends on voltage applied and resistance/impedance of the load. You can't apply 5.5 Amps unless you do that from a current source (or from too high a voltage) and it's unlikely that you have one unless you are in an electrical/electronics lab and know what you are talking about.
On the other hand, if you manage to stuff 5.5 Amps through a device that is only rated at 5 Amps, then you are forcing too much power into it. It will be electrically stressed and it may (or may not) fail.
Back to first statement - insufficient data.
In 50 VA the V stands for volts and the A is for amps. Hence the formula you are looking for is 50/240 = Amps.
50 amps
50 amps.
Amps * Volts = Watts. 50 Watts at 120 Volts = .4 Amps 50 Watts at 12 Volts = almost 4.25 Amps 50 Watts at 1 Volt = 50 Amps
50 amps.
in a home6000/120= 50 ampswatts/volts=amps
106 amps
50 amps
6 AWG will handle 50 amps with a voltage drop of about 4 volts. If you go to 4 AWG and limit to 50 amps your voltage drop will be 2.5 volts.
Amps = Watts/Volts55/12= 4.583333
Generally 40 amps continuous or 50 amps surge is safe.
50