It is a sodium bromide that is classified as an inorganic compounds there is a lot of stem cell research within the development.
The balanced equation for the formation of sodium bromide from sodium and bromine is: 2 Na + Br2 → 2 NaBr
The hydrolysis reaction of C4H9Br with NaOH can be represented as follows: C4H9Br + NaOH -> C4H9OH + NaBr This reaction involves the substitution of the bromine atom in C4H9Br with the hydroxide ion from NaOH, resulting in the formation of C4H9OH (butanol) and NaBr (sodium bromide).
The reaction between sodium (Na) and iron(III) bromide (FeBr3) would result in the formation of iron (III) bromide (FeBr3) and sodium bromide (NaBr). It follows the single displacement reaction: 2 Na + 2 FeBr3 -> 2 NaBr + 2 FeBr3.
The chloroform layer will turn purple or violet in color due to the formation of the organic bromine compound when NaBr reacts with Cl2 in water and then extracted into chloroform during the test.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
The melting point of NaBr is 747 oC.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
The chemical symbol for sodium bromide is NaBr.
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
No, NaBr is not an acid. It is the chemical formula for sodium bromide, which is a salt composed of sodium cations (Na+) and bromide anions (Br-).
2 Na + Br2 --> 2 NaBr
A formula unit of NaBr contains 2 atoms: 1 sodium and 1 bromine.