0
What else can I help you with?
How many moles are there in 0.684g MgCl2?
To find the number of moles in 0.684g of MgCl2, you need to divide the mass by the molar mass of MgCl2. The molar mass of MgCl2 is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl). Dividing 0.684g by 95.211 g/mol gives approximately 0.0072 moles of MgCl2.
What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
What is the mass of 1.5 moles of MgCl2?
The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl21.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
What is the ratio of Cl2 to Mg in MgCl2 if you have 0.03mol Mg and 0.06mol Cl2?
The balanced chemical equation for the reaction between Mg and Cl2 to form MgCl2 is: Mg + Cl2 -> MgCl2 From the equation, it can be seen that 1 mol of Mg reacts with 1 mol of Cl2 to produce 1 mol of MgCl2. Therefore, the ratio of Cl2 to Mg in MgCl2 would be 1:1.
How many moles of MgCl2 are there in 317 g of the compound?
To find the number of moles of MgCl2 in 317 g of the compound, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to get the number of moles: 317 g / 95.21 g/mol = 3.33 moles of MgCl2.
124 g of MgCl2 contains __.mol MgCl2?
Mgcl2 contain molar mass=24.31+ 2(35.45)= 95.21 g/mol 124g of Mgcl2 contains moles= 95.21* 124=11806.04moles
How many formula units make up 11.6g of mgcl2?
To find the number of formula units of MgCl2 in 11.6g, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to find the number of moles (0.122 mol). Since 1 mol of MgCl2 contains 1 formula unit, the number of formula units in 11.6g of MgCl2 is also 0.122 mol.
How many moles are there in 0.684g MgCl2?
To find the number of moles in 0.684g of MgCl2, you need to divide the mass by the molar mass of MgCl2. The molar mass of MgCl2 is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl). Dividing 0.684g by 95.211 g/mol gives approximately 0.0072 moles of MgCl2.
What is the value of x When a 1.63 g sample of MgCl2xH2O is heated to remove all water a mass of 0.762 g remains?
You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O
What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
100 mL of a 0.1 M MgCl2 solution contains?
use formula mv over 1000 ,so 20 x 0.3 over 1000 you 'll get 0.006 mol.
What is the mass of 1.5 moles of MgCl2?
The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl21.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
What is the molarity of 0.96 g MgCl2 in 0.500 L of solution?
To find the molarity, first calculate the moles of MgCl2 using its molar mass. Molar mass of MgCl2 = 95.21 g/mol Moles of MgCl2 = 0.96 g / 95.21 g/mol = 0.0101 mol Then, divide the moles by the volume in liters to find molarity: Molarity = 0.0101 mol / 0.500 L = 0.0202 M.
What is the theory yield of magnesium chloride when 5.6 grams of magnesium is reacted with elemental chlorine there is an excess of elemental chlorine the 5.60g magnesium is the limiting reactant?
magnesium + chlorine --> magnesium chloride Mg (s) + Cl2 (g) --> MgCl2 (s) 5.60 g Mg x 1 mol Mg x 1 mol MgCl2 x 95.21 g MgCl2 = 21.9 g MgCl2 ..................24.31 g Mg. 1 mol Mg........ 1 mol MgCl2
What is the ratio of Cl2 to Mg in MgCl2 if you have 0.03mol Mg and 0.06mol Cl2?
The balanced chemical equation for the reaction between Mg and Cl2 to form MgCl2 is: Mg + Cl2 -> MgCl2 From the equation, it can be seen that 1 mol of Mg reacts with 1 mol of Cl2 to produce 1 mol of MgCl2. Therefore, the ratio of Cl2 to Mg in MgCl2 would be 1:1.
How many formula units make up 21.2 of MgCl2?
To find out how many formula units of MgCl2 are in 21.2g, you can use the formula: (mass in grams)/(molar mass). The molar mass of MgCl2 is 95.211 g/mol. So, (21.2 g)/(95.211 g/mol) = 0.223 moles of MgCl2. Since there is 1 formula unit of MgCl2 in 1 mole, there are 0.223 formula units in 21.2g of MgCl2.
How many moles of MgCl2 are there in 317 g of the compound?
To find the number of moles of MgCl2 in 317 g of the compound, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to get the number of moles: 317 g / 95.21 g/mol = 3.33 moles of MgCl2.
