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How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
How many millilieters of 5.5 m naoh are needed to prepare 300 ml of 1.2 m naoh?
Use M1V1=M2V2 Where M is the concentration (5.5 m for M1 and 1.2 m for M2) and V is volume V1 is 300 ml and V2 is your unknown. Using this calculation for other questions be sure that units are all the same. So all molarities and all mL in this example.
How make 0.5ml of 2N NaOH?
To prepare 0.5 mL of 2N NaOH, you would need to dilute a higher concentration of NaOH solution. Assuming you have a 4N NaOH solution, you would mix 0.25 mL of the 4N solution with 0.25 mL of water to obtain 0.5 mL of 2N NaOH. Be cautious when handling concentrated NaOH solutions, as they are caustic and can cause skin irritation.
Can we make 1N NaOH solution from 0.1N NaOH solution?
Yes, you can make a 1N NaOH solution from a 0.1N NaOH solution by diluting it 10 times. For example, to make 1 liter of 1N NaOH solution, you would mix 100 ml of the 0.1N NaOH solution with 900 ml of water.
How to prepare 2N solution of NaOH in 10 ml of water?
To prepare a 2N solution of NaOH in 10 ml of water, you would need to calculate the amount of NaOH needed based on its molecular weight. Once you have determined the amount needed, dissolve it in 10 ml of water to make the solution. Remember to handle NaOH with caution as it is corrosive.
How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
How many millilieters of 5.5 m naoh are needed to prepare 300 ml of 1.2 m naoh?
Use M1V1=M2V2 Where M is the concentration (5.5 m for M1 and 1.2 m for M2) and V is volume V1 is 300 ml and V2 is your unknown. Using this calculation for other questions be sure that units are all the same. So all molarities and all mL in this example.
How make 0.5ml of 2N NaOH?
To prepare 0.5 mL of 2N NaOH, you would need to dilute a higher concentration of NaOH solution. Assuming you have a 4N NaOH solution, you would mix 0.25 mL of the 4N solution with 0.25 mL of water to obtain 0.5 mL of 2N NaOH. Be cautious when handling concentrated NaOH solutions, as they are caustic and can cause skin irritation.
Can we make 1N NaOH solution from 0.1N NaOH solution?
Yes, you can make a 1N NaOH solution from a 0.1N NaOH solution by diluting it 10 times. For example, to make 1 liter of 1N NaOH solution, you would mix 100 ml of the 0.1N NaOH solution with 900 ml of water.
How to prepare 2N solution of NaOH in 10 ml of water?
To prepare a 2N solution of NaOH in 10 ml of water, you would need to calculate the amount of NaOH needed based on its molecular weight. Once you have determined the amount needed, dissolve it in 10 ml of water to make the solution. Remember to handle NaOH with caution as it is corrosive.
How do you prepare 10 ml of 1M naoh?
To prepare 10 ml of 1M NaOH solution, you would need to dissolve 0.4 grams of NaOH (molar mass of NaOH is 40 g/mol) in enough distilled water to make a total volume of 10 ml. First, measure out 0.4 grams of NaOH using a balance. Then, add this solid NaOH to a small beaker and add distilled water while stirring until the total volume reaches 10 ml. Make sure to handle NaOH with care as it is a caustic substance.
How many mL of 2. 55 NaOH is needed to make 125 mL 0. 75 NaOH solution?
To determine the volume of 2.55 M NaOH needed to make a 125 mL 0.75 M NaOH solution, you can use the formula for dilution: M1V1 = M2V2. In this case, the initial concentration (M1) is 2.55 M, the final concentration (M2) is 0.75 M, and the final volume (V2) is 125 mL. Solving for V1 (the initial volume of 2.55 M NaOH needed) gives you approximately 415.69 mL.
How do you prepare 2N NaOH in 20 ml?
To prepare 2N NaOH in 20 ml, first calculate the amount of NaOH needed using the formula: (Molarity x Volume) / Normality. In this case, it would be (2 x 20) / 1 = 40 grams of NaOH. Then, carefully weigh out 40 grams of NaOH and dissolve it in enough water to make a total volume of 20 ml. Make sure to wear appropriate safety gear like gloves and goggles when handling NaOH.
How can you prepare 0.02 N NaOH solution if i have .2N NaOH?
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
If 20.0 mL of 150 M NaOH are used in a titration how many moles of NaOH are used?
To calculate the moles of NaOH used in the titration, multiply the volume (in liters) by the molarity. Converting 20.0 mL to liters (20.0 mL * 1 L/1000 mL = 0.020 L), the moles of NaOH used would be (0.020 L * 150 mol/L = 3.0 moles of NaOH).
What is the concentration of 300.0 mL of an HCl solution that required 16.4 mL of 6.90 M NaOH to neutralize?
The answer would be theoretically , 16.4* 6.9/300=0.3772M But one thing this concentration of NaOH is pretty high, and is not practical to make this solution. Concentration 6.9M means that you'll have to dissolve 40*6.9=286gm NaOH in one 1 litre water. Thus more than 4 gm are present in that 16.4 ml, which is very difficult.
A solution is prepared by mixing 360.0 mL of 0.25 M NaOH with 140.0 mL of 0.50 M NaOH and the final concentration is?
The concentration is 12,8 g/L NaOH.
