0
exp
- c=n/v donc c=m/M /v donc m=M*c*v=40*0.3*0.15=1.8g
- 1.8 dans 150ml d'eau
Wiki User
∙ 11y ago
Wiki User
∙ 11y ago3.6 g of NaOH when dissolved in 300 ml of water gives 0.3 N solution.
Normality = weight (in g) / (Molecular weight x Volume in litres)
Add your answer:
Earn +20 pts
How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?
You need 2,4 g NaOH (0,06 moles).
How to prepare 2N solution of NaOH in 10 ml of water?
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
How can you prepare 0.02 N NaOH solution if i have .2N NaOH?
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
27.0 ml of 0.45 m naoh is neutralized by 20 ml of an hcl solution the molarity of the hcl solution is?
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
Is CsOH more soluble in water than NaOH?
Most probably Caesium hydroxide is about 3 times more soluble than NaOH Solubility (in water) CsOH: 300 g/100 mL at 30 °C) Solubility (in water) NaOH: 111 g/100 mL at 20 °C
How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?
You need 2,4 g NaOH (0,06 moles).
How to prepare 2N solution of NaOH in 10 ml of water?
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
How can you prepare 0.02 N NaOH solution if i have .2N NaOH?
In order to make 0.02 N NaOH from 0.2 N NaOH, one needs to dilute it by 10 x (10 fold). Depending on the volume of 0.02 N NaOH needed, that will determine the volume of 0.2 N used. For example, to make 100 ml of 0.02 N NaOH, you would dilute 10 mls of 0.2 N to 100 ml. This is seen in the following calculation: (x ml)(0.2 N NaOH) = (100 ml) (0.02 N NaOH) and x = 10 ml
Explain how you would make 50 ml of 0.15 m NaOH solution from a 3.05 m NaOH solution?
Take 2.409 ml of 3.05M NaOH mix c a balance of H2O to form 50ml of mixture
27.0 ml of 0.45 m naoh is neutralized by 20 ml of an hcl solution the molarity of the hcl solution is?
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
What is the concentration of 300.0 mL of an HCl solution that required 16.4 mL of 6.90 M NaOH to neutralize?
The answer would be theoretically , 16.4* 6.9/300=0.3772M But one thing this concentration of NaOH is pretty high, and is not practical to make this solution. Concentration 6.9M means that you'll have to dissolve 40*6.9=286gm NaOH in one 1 litre water. Thus more than 4 gm are present in that 16.4 ml, which is very difficult.
Is CsOH more soluble in water than NaOH?
Most probably Caesium hydroxide is about 3 times more soluble than NaOH Solubility (in water) CsOH: 300 g/100 mL at 30 °C) Solubility (in water) NaOH: 111 g/100 mL at 20 °C
How do you make a 2 percent NaOH soluiton from 50 percent NaOH solution?
First you must either know how much 50% NaOH you want to start with or know how much 2% NaOH you need at the end. Let's say you want 1L of the 2% NaOH. Use this equation, and solve for x, where in this case, x is the volume of 50% NaOH needed. (50% NaOH)x = (2%) * 1000 ml 0.5x = 0.02(1000) x = 20/0.5 = 40 Therefore, 40 ml of 50% NaOH in 960 ml water will produce 2% NaOH. Use a 1000 ml volumetric flask to be most precise.
How many millilieters of 5.5 m naoh are needed to prepare 300 ml of 1.2 m naoh?
Use M1V1=M2V2 Where M is the concentration (5.5 m for M1 and 1.2 m for M2) and V is volume V1 is 300 ml and V2 is your unknown. Using this calculation for other questions be sure that units are all the same. So all molarities and all mL in this example.
What is the number of moles of NaOH in 16.5 mL of 0.750 Molar NaOH?
0.0165 (L) * 0.750 (mol/L) = 0.0124 mol NaOH in 16.5 mL
5.012g of oxalic acid hydrate is dissolved in enough water to make 100 ml of solution. this solution is stitrated with a standardized NaOH solution. It required 39.40 ml of 2.02 M NaOH to reach the?
endpoint
How many ml of 250 M NaOH are required to neutralize 30.4 ml of 152 M HCl?
M1V1=M2V2... By plugging in, you get 18.48 mL of NaOH
