Well other than the fact that it needs to lose one (group 1) normally in an ionic compound (metal and non metal bonding), it would be different seeming how your teacher/tutor defines it.
One chlorine atom has 7 electrons in its outer shell, and sodium has 1 electron in its outer shell. Therefore, sodium can donate its electron to chlorine, forming a stable compound where chlorine has a full outer shell with 8 electrons.
Sodium has 1 electron in its outer shell, and it needs to lose that one electron to achieve a full outer shell (valence shell) with 8 electrons. By losing this one electron, sodium will achieve a stable electron configuration similar to that of the noble gas neon.
Sodium has 1 valence electron in its outer shell. By losing this electron, sodium achieves a full outer shell, which is more stable. This stable configuration is achieved by following the octet rule, where atoms tend to gain, lose, or share electrons to have 8 electrons in their outer shell.
Calcium has a full 4s sublevel, but does not have a full "outer shell", per se, because it is not a noble gas.
Yes, both sodium and chlorine ions are stable. Sodium ion (Na+) has a full outer shell of electrons, following the octet rule, while chlorine ion (Cl-) has gained an electron to achieve a full outer shell.
One chlorine atom has 7 electrons in its outer shell, and sodium has 1 electron in its outer shell. Therefore, sodium can donate its electron to chlorine, forming a stable compound where chlorine has a full outer shell with 8 electrons.
Just one.
Sodium has 1 electron in its outer shell, and it needs to lose that one electron to achieve a full outer shell (valence shell) with 8 electrons. By losing this one electron, sodium will achieve a stable electron configuration similar to that of the noble gas neon.
Sodium would need to gain 7 electrons to fill its valance shell. Instead of doing that, however, sodium will lose the one valence electron it does have, leaving behind the shell below it, which is already full.
Sodium has 1 valence electron in its outer shell. By losing this electron, sodium achieves a full outer shell, which is more stable. This stable configuration is achieved by following the octet rule, where atoms tend to gain, lose, or share electrons to have 8 electrons in their outer shell.
Calcium has a full 4s sublevel, but does not have a full "outer shell", per se, because it is not a noble gas.
Yes, both sodium and chlorine ions are stable. Sodium ion (Na+) has a full outer shell of electrons, following the octet rule, while chlorine ion (Cl-) has gained an electron to achieve a full outer shell.
Bromine has 7 electrons in its outer shell and needs to gain one electron to have a full outer shell and become an ion. It will gain this electron from an atom that has one electron in its outer shell such as Lithium or Sodium.
Sodium has one electron in its outer shell, so it tends to lose that electron to achieve a full outer shell. This makes sodium more stable as it follows the octet rule by having a complete outer electron shell with eight electrons.
The transfer of an electron between a sodium atom and a chlorine atom occurs because sodium has one electron in its outer shell that it wants to lose to achieve a more stable electron configuration, while chlorine has seven electrons in its outer shell and can gain one from sodium to complete its outer shell and achieve stability by forming a full octet. This transfer of electrons results in the formation of sodium chloride, an ionic compound.
When a sodium atom loses an electron in its outer shell, it forms a positively charged sodium ion (Na+). This process happens in order to achieve a stable electron configuration similar to that of a noble gas, which typically have a full outer shell of electrons.
Sodium does not have a full outer valence shell. It has one electron in its outermost shell, which makes it very reactive and likely to lose that electron to achieve stability.