18 grams of water contain 1 mole. so 1 gram contains 1/18 moles of water.
1 gram carbon (1 mole C/12.01 grams) = 0.08 moles carbon ===============
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
1 mole is equal to 18 grams of H2O, so 60 grams is 3.33 moles.
For the reaction 2 H2 + O2 -> 2 H2O, we see that 1 mole of O2 produces 2 moles of H2O. Therefore, to produce 10.2 moles of H2O, we would need 5.1 moles of O2.
To find the number of moles of water molecules in a 27 gram sample, you need to divide the mass by the molar mass of water (18.015 g/mol). 27 g / 18.015 g/mol = approximately 1.5 moles of water molecules.
1 gram carbon (1 mole C/12.01 grams) = 0.08 moles carbon ===============
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
1 mole is equal to 18 grams of H2O, so 60 grams is 3.33 moles.
For the reaction 2 H2 + O2 -> 2 H2O, we see that 1 mole of O2 produces 2 moles of H2O. Therefore, to produce 10.2 moles of H2O, we would need 5.1 moles of O2.
2.95 mole H2O (2 moles H/1 mole H2O) = 5.90 moles hydrogen ------------------------------
To find the number of moles of water molecules in a 27 gram sample, you need to divide the mass by the molar mass of water (18.015 g/mol). 27 g / 18.015 g/mol = approximately 1.5 moles of water molecules.
In one molecule of H2O, there are 2 moles of hydrogen (H) and 1 mole of oxygen (O).
1 mole H2O = 18.015g H2O 1.57mol H2O x 18.015g H2O/1mol H2O = 28.3g H2O
To determine the number of moles of water in 72.08g of H2O, we first need to calculate the molar mass of water (H2O). The molar mass of water is approximately 18.015 g/mol (2 hydrogen atoms with a molar mass of 1.008 g/mol each, and 1 oxygen atom with a molar mass of 16.00 g/mol). Next, we use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 72.08g / 18.015 g/mol ≈ 4 moles of water. Therefore, there are approximately 4 moles of water in 72.08g of H2O.
5 moles H2O (1 mole O/1 mole H2O)(6.022 X 1023/1 mole O)(1 mole O atoms/6.022 X 1023)= 5 moles oxygen atoms=================( as you see this is a formal set up that you do not need to use fully as Avogadro's number is over itself as a form of one )5 moles H2O (2 moles H/1 mole H2O)6.022 X 1023/1 mole H)(1 mole H atoms/6.022 X 1023)= 10 moles hydrogen atoms====================
N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced
2H2 + O2 --> 2H2OFor every 2 moles of H2, 2 moles of H2O will be produced (i.e., a 1:1 ratio). So to produce 8.25 moles of H2O you will also need 8.25 moles of H2