To determine the number of moles of water in 72.08g of H2O, we first need to calculate the molar mass of water (H2O). The molar mass of water is approximately 18.015 g/mol (2 hydrogen atoms with a molar mass of 1.008 g/mol each, and 1 oxygen atom with a molar mass of 16.00 g/mol).
Next, we use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 72.08g / 18.015 g/mol ≈ 4 moles of water. Therefore, there are approximately 4 moles of water in 72.08g of H2O.
2.95 mole H2O (2 moles H/1 mole H2O) = 5.90 moles hydrogen ------------------------------
There is no nitrogen in water.
Two moles of water are produced.
6,49 moles of water are obtained.
The answer is 8,33 moles.
H2O or water doesn't have any helium in it.
3.2 moles of water (H2O)
2.95 mole H2O (2 moles H/1 mole H2O) = 5.90 moles hydrogen ------------------------------
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
There is no nitrogen in water.
Two moles of water are produced.
To find the number of moles in 117g of H2O, you first need to determine the molar mass of H2O, which is approximately 18 g/mol. Then, divide the mass given (117g) by the molar mass to find the number of moles. In this case, 117g of H2O is equal to 6.5 moles.
6,49 moles of water are obtained.
Sulfuric acid is not obtained from water.
The answer is 0,44 moles.
The answer is 8,33 moles.
In one mole of this solution, there are seven moles of H2O.