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How many moles of atoms are there in 75.10 grams of chlorine?
To find the number of moles of atoms in 75.10 grams of chlorine, you need to first determine the molar mass of chlorine. Chlorine has a molar mass of approximately 35.45 g/mol. Next, you can use the formula Moles = Mass / Molar Mass to calculate the moles of chlorine atoms in 75.10 grams. This would result in approximately 2.12 moles of chlorine atoms.
How many grams of chlorine are needed to produce 1.5 mole chloroform?
To produce 1 mole of chloroform, you need 3 moles of chlorine. So, to produce 1.5 moles of chloroform, you would need 4.5 moles of chlorine. Converting moles to grams by using the molar mass of chlorine (35.5 g/mol) gives you 160.5 grams of chlorine required.
How many grams is 64 moles of Cl?
To find the mass of 64 moles of Cl (chlorine), you need to multiply the number of moles by the molar mass of Cl. The molar mass of Cl is approximately 35.45 g/mol. Therefore, 64 moles of Cl would be approximately 2267.2 grams (64 moles x 35.45 g/mol).
How many grams of AuCl3 can be made from 100.0 grams of chlorine by this reaction Au plus Cl3 AuCl3?
The molar mass of chlorine is 35.45 g/mol. From the equation, 3 moles of chlorine are needed to form 1 mole of AuCl3. Therefore, 100.0 grams of chlorine corresponds to 100.0 g / 35.45 g/mol = 2.82 moles of Cl2. This would allow the formation of 2.82 / 3 = 0.94 moles of AuCl3. Finally, the molar mass of AuCl3 is 303.33 g/mol, which means 0.94 moles of AuCl3 would be equivalent to 0.94 mol * 303.33 g/mol = 285.53 grams of AuCl3.
How many moles of chlorine are in 3.4 moles of hydrolic acid?
In hydrochloric acid (HCl), there is one mole of chlorine for every mole of hydrochloric acid. Therefore, in 3.4 moles of hydrochloric acid, there are also 3.4 moles of chlorine.
How many grams are there in 0.100 mols of chlorine?
Multiply the moles given, by the atomic mass of chlorine and you have your answer. (3.55 Grams)
How many moles of atoms are there in 75.10 grams of chlorine?
To find the number of moles of atoms in 75.10 grams of chlorine, you need to first determine the molar mass of chlorine. Chlorine has a molar mass of approximately 35.45 g/mol. Next, you can use the formula Moles = Mass / Molar Mass to calculate the moles of chlorine atoms in 75.10 grams. This would result in approximately 2.12 moles of chlorine atoms.
How many grams of chlorine are needed to produce 1.5 mole chloroform?
To produce 1 mole of chloroform, you need 3 moles of chlorine. So, to produce 1.5 moles of chloroform, you would need 4.5 moles of chlorine. Converting moles to grams by using the molar mass of chlorine (35.5 g/mol) gives you 160.5 grams of chlorine required.
How many grams is 64 moles of Cl?
To find the mass of 64 moles of Cl (chlorine), you need to multiply the number of moles by the molar mass of Cl. The molar mass of Cl is approximately 35.45 g/mol. Therefore, 64 moles of Cl would be approximately 2267.2 grams (64 moles x 35.45 g/mol).
How many moles is 142gram of chlorine gas?
The answer is it's atomic mass converted to grams... Chlorine has an atomic mass of 35.45 So 1 mol of chlorine would be 35.45g you have 142g of it, so you divide 142 by 35.45 and get 4.005 moles of chlorine
How many moles are in 0.100 gams of chlorine?
I believe it's 0.00282 moles or 0.003 moles if you want to round it up to 3 decimal places. I'm assuming that 0.100 gams is a typo and should really be "grams"!The formula is : n = m X Mw, where n = moles, m = mass (in grams) and Mw is Molecular Weight (or MM - Molecular Mass). The Mw (or MM) of Chlorine is 35.453 (see the Periodic table) and the mass is 0.100 grams, so 0.100 divided by 35.453 = 0.00282 or 0.003 rounded up to 3 places.
When 10.0 grams of calcium reacts with 20.0 grams of chlorine gas, how many grams of calcium chloride can be produced Which reactant is in excess and which is the limiting reactant?
The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.
What is 16 grams of oxygen how many moles?
16 grams of oxygen how many moles is 0,5 moles.
How many molecules of chlorine are in 134.5 grams of chlorine?
http://en.wikipedia.org/wiki/Chlorine 1 mol of chlorine (Cl2) weighs (2*35.45 =)70,90 grams 134,5 grams of chlorine is (134,5/70,9 =) 1,897 mol of chlorinegas. 1,897 * 6,02 * 10^23 = 1,142 * 10^24 molecules of Cl2
How many grams of AuCl3 can be made from 100.0 grams of chlorine by this reaction Au plus Cl3 AuCl3?
The molar mass of chlorine is 35.45 g/mol. From the equation, 3 moles of chlorine are needed to form 1 mole of AuCl3. Therefore, 100.0 grams of chlorine corresponds to 100.0 g / 35.45 g/mol = 2.82 moles of Cl2. This would allow the formation of 2.82 / 3 = 0.94 moles of AuCl3. Finally, the molar mass of AuCl3 is 303.33 g/mol, which means 0.94 moles of AuCl3 would be equivalent to 0.94 mol * 303.33 g/mol = 285.53 grams of AuCl3.
How many atoms of chlorine are in 2.00 moles of CCl4?
The number of chlorine atoms in 2,00 moles of CCl4 is 48,113.10e23.
How many moles of hydrogen chloride can be produced from 0.490 grams of Hydrogen and 50.0 grams of chlorine?
The atomic mass of hydrogen is 1.008 and that for chlorine is 35.45. The moles of hydrogen available are therefore 0.490/1.008 = 0.486 and the moles of chlorine available, 50/35.45, are greater than 1. Each molecule of hydrogen chloride requires one atom each of chlorine and hydrogen. Therefore, with the specified conditions, hydrogen is stoichiometrically limiting, and 0.486 moles of HCl can be made.
