There is no "defined" number of CO2 that are produced in respiration. The number changes with the efficiency of the cardiopulmonary system in any given person.
But as a general rule, when the Hemoglobin in the blood return a carbon dioxide molecule from the muscles during metabolism of food and nutrients, it is a simply chemical formula: C + 02 = C02. In respiration, oxygen is only provided to the body in a diatomic form (O2) in the general case. However, if Carbon MONOxide is present in the air a person inhales, it will bond to the Hgb over any oxygen.
You need to dissolve 180 grams of glucose in water and make it up to 1000ml. this produces 1 M Glucose solution.
The balanced chemical equation for the reaction is: C6H12O6 + 6O2 -> 6CO2 + 6H2O The molar mass of glucose is 180 g/mol, so 126 g of glucose is 0.7 moles. From the equation, 1 mole of glucose produces 6 moles of CO2, so 0.7 moles of glucose will produce 4.2 moles of CO2. Using the ideal gas law, at STP conditions, 4.2 moles of CO2 will occupy 94.5 liters.
To find the molality of a solution, you need the mass of the solvent (usually water) in kilograms and the number of moles of solute (glucose). Given that the solution is 7.80% glucose by weight, you can calculate the mass of glucose in the solution and then convert it to moles using the molar mass of glucose. From there, you can find the molality by dividing the moles of glucose by the mass of the solvent in kilograms.
To find the molarity of the sugar solution, we first need to convert the mass of glucose to moles. The molar mass of glucose (C6H12O6) is 180 g/mol. So, 80 g of glucose is equal to 80/180 = 0.444 moles. Next, calculate the molarity by dividing moles of glucose by liters of solution (0.75 L), Molarity = 0.444 moles / 0.75 L = 0.592 M.
To find the number of moles, use Avogadro's number: 1 mole = 6.022 x 10^23 molecules. Divide the number of molecules given by Avogadro's number to get the number of moles. In this case, 2.4088 x 10^24 molecules ÷ 6.022 x 10^23 molecules/mole ≈ 4 moles of glucose.
To calculate the cellular respiration rate in moles of glucose per minute, you need to convert the volume of CO2 produced into moles using the ideal gas law. Then, you can use the stoichiometry of the cellular respiration reaction to relate the moles of CO2 produced to moles of glucose consumed. Once you have both values, you can determine the rate of glucose consumption per minute.
Do you mean this reaction? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles oxygen required. --------------------------------
One mole of glucose yields 36 moles of ATP through cellular respiration, while one mole of triglyceride (composed of lauric acid) yields 129 moles of ATP through beta oxidation and the citric acid cycle. Therefore, with 3.5 moles of each, the triglyceride will produce more energy by yielding 451.5 moles of ATP, compared to the 126 moles produced by the glucose.
You need to dissolve 180 grams of glucose in water and make it up to 1000ml. this produces 1 M Glucose solution.
In cellular respiration, one mole of glucose produces approximately 38 moles of ATP, and each mole of ATP yields around 7.3 kilocalories when broken down. So, 1.5 moles of glucose would yield around 38 * 1.5 * 7.3 = 415.5 kilocalories in total.
To form ethanol, the chemical equation shows that one mole of glucose is converted to two moles of ethanol. The molar mass of glucose is around 180 g/mol and that of ethanol is around 46 g/mol. Therefore, to produce 127g of ethanol, you would need 127g/(46g/mol) = 2.76 moles of ethanol. Since glucose to ethanol is a 1:2 ratio, you would need half as many moles of glucose, which would be 1.38 moles of glucose.
6mol
2.,7 moles of glucose have 486,432 g.
The number of moles is 2,997.
This process is known as respiration.(The liberation of energy from food) Glucose a simple sugar(C6H12O6) is burnt in 6 moles of oxygen to give the bi-products of 6 moles of water and 6 moles of carbon dioxide and energy which may be stored as ATP(adenosine triphosphate) in muscles to do work. {The glucose found in food is basically reacted with oxygen to give CO2,metabolic water and energy. (In a nutshell)}
0,83moles glucose are burned.
To determine the mass of glucose that must be metabolized to produce 145 grams of water, we can use the balanced equation for the combustion of glucose: (C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O). From the equation, 1 mole of glucose produces 6 moles of water. The molar mass of water (H₂O) is approximately 18 g/mol, so 145 g of water is about 8.06 moles (145 g / 18 g/mol). Therefore, to produce this amount of water, approximately 1.34 moles of glucose are needed (8.06 moles of water / 6). The molar mass of glucose (C₆H₁₂O₆) is about 180 g/mol, so the mass of glucose required is approximately 241.2 grams (1.34 moles × 180 g/mol).