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How many moles of KCl would be diissolved in 4 L of water to make a 2 M solution?
Wiki User
∙ 10y ago
8 mole KCl (lower case 'el', not KCI with uppercase 'ai') in added up to 4 L (final volume) with water makes 2 M solution.
Wiki User
∙ 10y ago
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How many moles of KCI would be dissolved in 4 L of water to make 2 M solution?
8 moles
What is the molarity when water is added to 2 moles of sodium chloride to make 0.5 liter of solution?
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
How would you make a 2 M solution of a compound?
By dissolving 2.0 moles of the compound in water and then, after complete dissolution, fill it up to a total volume 1.0 L with water.
What is the molarity of a solution when 25.0 g of aluminum sulfite is dissolved in distilled water and made up to 175.0 ml of solution?
Al2(SO3)3 has r.f.m.= (2x27 + 3x32 + 9x16) = 294 Thus 25 g is 25/294 = 0.085 moles of aluminium sulfite. We have 0.085 moles in 175 ml of solution, which would be 0.085 x 1000/175 moles in a litre = 0.486 M
What is a solution of salt and water contains 75 grams of water per 150 milliliters of the solutionIf 1 mole of water weight 16 grams what moles of water would be present in 30 milliliters of the solu?
75 g sodium chloride in 150 mL water is a supersaturated solution.
How many moles of KCI would be dissolved in 4 L of water to make 2 M solution?
8 moles
How would one make M solution of a compound?
By dissolving 2 moles of the compound in 1 L of water
How many moles of KCI would be dissolved in 4 liters of water to make a 2 Molar solution?
We need 8 moles potassium chloride.
What is the molarity when water is added to 2 moles of sodium chloride to make 0.5 liter of solution?
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
How would one make 2 M solution of compound?
By dissolving 2 moles of the compound in 1 L of water
How would one make 2 M solution of a compound?
By dissolving 2 moles of the compound in 1 L of water
What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
How many moles of KBR are there in 100 mL if a 0.75 M Solution?
There would be 0.75 moles in 1 liter of solution. You have 100 mL which is in fact 0.1 liters. so you would have 0.1 of 0.75 moles. 0.1 x 0.75 = 0.075 moles.
When a solution is diluted does it change the number of moles dissolved?
The number of moles of a solute will not change as a solution is diluted, however, the concentration of the solute will decrease. If you were to evaporate the water from the diluted solution, you would have the same number of moles of solute as when you started. You can test this by comparing the mass of the solute before producing the solution to the mass of the solute after the solution was diluted. The two masses should be the same.
How would you make a 2 M solution of a compound?
By dissolving 2.0 moles of the compound in water and then, after complete dissolution, fill it up to a total volume 1.0 L with water.
What is the molarity of a solution when 25.0 g of aluminum sulfite is dissolved in distilled water and made up to 175.0 ml of solution?
Al2(SO3)3 has r.f.m.= (2x27 + 3x32 + 9x16) = 294 Thus 25 g is 25/294 = 0.085 moles of aluminium sulfite. We have 0.085 moles in 175 ml of solution, which would be 0.085 x 1000/175 moles in a litre = 0.486 M
How many grams of KCl would you need to make 250 ml of a 0.5-M Solution w work?
Molar mass of KCl = 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol. A 0.5 M solution is required (0.5 mol/L or 0.5 moles per litre). 0.5 moles of KCl is 0.5 mol x 74.5 g/mol = 37.25 g. Dissolving this 37.25 g of KCl in a litre of water would give a 0.5 M solution. If 1 L or 1000 mL of 0.5 M solution contains 0.5 moles then 1 mL of the same concentration solution would contain 0.5/1000 moles and 250 mL would contain 250 x 0.5/1000 moles = 0.125 moles. 0.125 moles of KCl is 0.125 mol x 74.5 g/mol = 9.31 g.
