8 mole KCl (lower case 'el', not KCI with uppercase 'ai') in added up to 4 L (final volume) with water makes 2 M solution.
To make a 2 M solution of KCl in 4 L of water, you would need 8 moles of KCl. This is because Molarity (M) is defined as moles of solute divided by liters of solution. In this case, 2 M means 2 moles of KCl per liter, which totals 8 moles for 4 liters.
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
To dissolve 2 moles of NaOH in 6 kg of water, you would need to calculate the molarity of the NaOH solution. First, you would find the molar mass of NaOH (40 g/mol) and then divide the moles by the mass of water in kg to find the molarity. This would be approximately 0.33 mol/L.
In the given solution, there are 75 grams of water in 150 ml. This means there are 0.5 grams of water per milliliter. Therefore, in 30 ml of the solution, there would be 15 grams of water. To find the moles of water, divide the mass of water by its molar mass (16 g/mol), so in 30 ml of the solution, there would be 15/16 = 0.9375 moles of water present.
To make a 2 M solution of KCl in 4 L of water, you would need 8 moles of KCl. This is because Molarity (M) is defined as moles of solute divided by liters of solution. In this case, 2 M means 2 moles of KCl per liter, which totals 8 moles for 4 liters.
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
To dissolve 2 moles of NaOH in 6 kg of water, you would need to calculate the molarity of the NaOH solution. First, you would find the molar mass of NaOH (40 g/mol) and then divide the moles by the mass of water in kg to find the molarity. This would be approximately 0.33 mol/L.
In the given solution, there are 75 grams of water in 150 ml. This means there are 0.5 grams of water per milliliter. Therefore, in 30 ml of the solution, there would be 15 grams of water. To find the moles of water, divide the mass of water by its molar mass (16 g/mol), so in 30 ml of the solution, there would be 15/16 = 0.9375 moles of water present.
This molarity is 3 M.
By dissolving 2 moles of the compound in 1 L of water
We need 8 moles potassium chloride.
Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------