Only possible to calculate approximately (without knowing densities of all solutions) when 'percent' means 'gram per 100 ml' or 'ml per 100 ml'
Solve the following equations to find V1 and V2:
Outcome: 632 and 168 ml respectively, but this is an approximation! (due to the ignoring of volume contraction: mixing will result in LESS ml's than 800 ml, so concentration will be more than 15%)
The amount of NaCl in the final solution is 5g, and the total volume of the solution is 45mL. To find the percent strength, divide the mass of NaCl by the total volume of the solution and multiply by 100: (5g / 45mL) x 100 ≈ 11.1%.
To prepare a 2% NaCl (w/v) solution, you would dissolve 2 grams of NaCl in enough water to make 100 mL of solution. This means you would add 2 grams of NaCl to a flask and then add water until the total volume reaches 100 mL.
Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl
To prepare a 4.00 M NaCl solution, first calculate the moles of NaCl in 23.4 g. Then, determine the volume of water needed to make a total volume of 100.0 mL minus the volume of NaCl solution. Add the water to the NaCl to make a 100.0 mL solution.
First calculate the mass you need from NaCl I will calculate it for you now: 100 cm3= 0,100 L n (NaCl) = 0,1 mol/dm3 * 0,100 L = 0,01 mol m (NaCl) = n*Mm = 0,01 mol * ( 22,99+35,45) g/mol = 0,01 mol * 58,44 g/mol = 0,5844 g You will need 0,5844 g NaCl and you will mix it woth 100 cm3 water
The answer is 0,9 g pure, dried NaCl.
If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.
To make a 15.00% by mass aqueous solution with NaCl, the mass of NaCl is 255.0g. This means that 15.00g of NaCl is present in every 100.00g of solution. To find the mass of water needed, first calculate the mass of NaCl in the final solution, then subtract this amount from the total mass of the solution (water + NaCl).
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
The amount of NaCl in the final solution is 5g, and the total volume of the solution is 45mL. To find the percent strength, divide the mass of NaCl by the total volume of the solution and multiply by 100: (5g / 45mL) x 100 ≈ 11.1%.
To prepare a 2% NaCl (w/v) solution, you would dissolve 2 grams of NaCl in enough water to make 100 mL of solution. This means you would add 2 grams of NaCl to a flask and then add water until the total volume reaches 100 mL.
Dissolve 3 g NaCl in 100 mL water.
The answer is 26,3 g.
Reactions are: 2Na + Cl2 = 2NaCl NaOH + HCl = NaCl + H2O
Moles of NaCl=6*3=18mol Mass needed=[35.5+23]*18=1053g
Sodium chloride is a solute when is dissolved in water (the solvent).
Dissolve 5 g salt in 100 mL water at 20 0C.