Helium comes very close to ideal at STP since it is so small and monatomic. In reality most gases are pretty indistinguishable from ideal at STP because the molecules are so far apart that their individual volumes are negligible compared to the space they are in and the molecules are so far apart that they exert negligible force on each other.
1 mole of gas at STP (standard temperature and pressure) occupies 22.4 liters of volume. This is known as the molar volume of a gas at STP. Additionally, the gas has a pressure of 1 atmosphere and a temperature of 273 K at STP.
By using the ideal gas law, at STP (standard temperature and pressure), 1 mole of any ideal gas occupies 22.4 liters. Therefore, in 4.00 liters of CO2 gas at STP there would be 4.00/22.4 = 0.179 moles of CO2 present.
At Standard Temperature and Pressure (STP), one mole of any ideal gas will occupy 22.4 liters. So to fill a 2.0 liter container at STP, you would need 2.0/22.4 = 0.089 moles of an ideal gas. This means any gas that is present in that amount and under those conditions can uniformly fill the container.
At STP, 1 mole of any ideal gas occupies 22.4 liters. Therefore, 5 liters of NO2 at STP will represent 0.22 moles (5/22.4), and this is the case for any other ideal gas. So, the answer is that 5 liter of ANY ideal gas will have the same number of molecules as 5 liters of NO2.
To calculate the volume of CO2 at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT. First, find the number of moles of CO2 using the ideal gas law equation. Then, use the molar volume of a gas at STP (22.4 L/mol) to find the volume at STP.
1 mole of an ideal gas at STP occupies 22.4 liters. If STP is 'close' to the boiling point a real gas may deviate from ideal behavior and thus the volume will not be as predicted.
1 mole of gas at STP (standard temperature and pressure) occupies 22.4 liters of volume. This is known as the molar volume of a gas at STP. Additionally, the gas has a pressure of 1 atmosphere and a temperature of 273 K at STP.
By using the ideal gas law, at STP (standard temperature and pressure), 1 mole of any ideal gas occupies 22.4 liters. Therefore, in 4.00 liters of CO2 gas at STP there would be 4.00/22.4 = 0.179 moles of CO2 present.
The volume is 22,710 980(38) litres for the ideal gas.
Ideal gas equation. PV = nRT ===============
Using the ideal gas law, at STP (standard temperature and pressure), 1 mole of gas occupies 22.4 liters. Therefore, a balloon with 560 liters at STP would contain 25 moles of gas (560 liters / 22.4 liters/mole).
No; the ideal gas is theoretical concept.STP is an acronym for standard temperature and pressure; an important conditions for the measurements in similar situations.
At Standard Temperature and Pressure (STP), one mole of any ideal gas will occupy 22.4 liters. So to fill a 2.0 liter container at STP, you would need 2.0/22.4 = 0.089 moles of an ideal gas. This means any gas that is present in that amount and under those conditions can uniformly fill the container.
At STP, 1 mole of any ideal gas occupies 22.4 liters. Therefore, 5 liters of NO2 at STP will represent 0.22 moles (5/22.4), and this is the case for any other ideal gas. So, the answer is that 5 liter of ANY ideal gas will have the same number of molecules as 5 liters of NO2.
Using the ideal gas law, we can calculate the volume of the gas at STP (standard temperature and pressure). Given that the molar mass of Chlorine gas is approximately 71 g/mol, 10.0 grams of Chlorine gas would be approximately 0.14 moles. At STP, 1 mole of any ideal gas occupies 22.4 liters, so 0.14 moles would occupy approximately 3.14 liters.
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
To calculate the volume of CO2 at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT. First, find the number of moles of CO2 using the ideal gas law equation. Then, use the molar volume of a gas at STP (22.4 L/mol) to find the volume at STP.