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How many grams are there in 4.50 moles of barium nitrite?
To convert moles to grams, multiply the number of moles by the molar mass of the compound. The molar mass of barium nitrite (Ba(NO2)2) can be calculated as: 1Ba + 2(NO2) = 137.33 + 2(46.01) = 229.35 g/mol. So, 4.50 moles of barium nitrite would be 4.50 moles x 229.35 g/mol = 1032.08 grams of barium nitrite.
How many grams of barium chloride are there in 286 moles?
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.
How many moles are in 317.0 g of BaOH2?
To find the number of moles in 317.0 g of Ba(OH)2, first calculate the molar mass of Ba(OH)2 which is 171.34 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, the number of moles would be 317.0 g / 171.34 g/mol ≈ 1.85 moles.
What is the mass of 3 moles of barium?
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
How many moles are there in 37 grams of calcium hydroxide?
To find the number of moles in 37 grams of calcium hydroxide, you need to divide the given mass by the molar mass of calcium hydroxide. The molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol. Therefore, 37 grams of calcium hydroxide is equal to 0.499 moles.
Barium hydroxide contained 2.74g in 100cm of water titration of 20cm required 18.7cm of a hydrochloric acid solution for complete neutralization what is the molarity of the barium hydroxide?
To find the molarity of the barium hydroxide solution, first calculate the number of moles of hydrochloric acid used in the titration. Then use the stoichiometry of the reaction to determine the number of moles of barium hydroxide present. Finally, divide the moles of barium hydroxide by the volume of the solution in liters to get the molarity.
How many moles of barium are present in a sample having a mass of 22.3 grams?
To determine the number of moles present, we first need to find the molar mass of barium (Ba), which is approximately 137.33 g/mol. Next, we use the formula n = m/M, where n is the number of moles, m is the mass of the sample (22.3 grams), and M is the molar mass (137.33 g/mol). By substituting these values, we find that there are approximately 0.162 moles of barium in the sample.
How many grams are there in 4.50 moles of barium nitrite?
To convert moles to grams, multiply the number of moles by the molar mass of the compound. The molar mass of barium nitrite (Ba(NO2)2) can be calculated as: 1Ba + 2(NO2) = 137.33 + 2(46.01) = 229.35 g/mol. So, 4.50 moles of barium nitrite would be 4.50 moles x 229.35 g/mol = 1032.08 grams of barium nitrite.
What is the mass in grams of 25 mol of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
How many grams of barium chloride are there in 286 moles?
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.
How many grams of solid barium hydroxide are needed to exactly neutralize 14.7 mL of a 0.597 M perchloric acid solution?
To find the number of moles of perchloric acid, use the formula Molarity (M) = moles/volume (L). Then, since the balanced equation for the reaction is 2 HClO4 + Ba(OH)2 -> Ba(ClO4)2 + 2 H2O, you need 2 moles of Ba(OH)2 for every 2 moles of perchloric acid neutralized. After finding the moles of perchloric acid, convert it to grams of barium hydroxide using the molar mass of Ba(OH)2.
How many grams of sodium hydroxide are present in 675 mL of a 0.500M solution?
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
What is 83 grams of sodium hydroxide in moles?
For this you need the atomic (molecular) mass of NaOH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaOH= 40.083.0 grams NaOH / (40.0 grams)= 2.08 moles NaOH
How many moles of sodium hydroxide are in 40 grams of sodium hydroxide?
To find the number of moles in 40 grams of sodium hydroxide, you first need to calculate the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Then, you divide the given mass by the molar mass to get the number of moles. So, 40 grams divided by 40 g/mol is equal to 1 mole of NaOH.
How many moles are in 317.0 g of BaOH2?
To find the number of moles in 317.0 g of Ba(OH)2, first calculate the molar mass of Ba(OH)2 which is 171.34 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, the number of moles would be 317.0 g / 171.34 g/mol ≈ 1.85 moles.
What is the mass of 3 moles of barium?
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
How many moles are there in 37 grams of calcium hydroxide?
To find the number of moles in 37 grams of calcium hydroxide, you need to divide the given mass by the molar mass of calcium hydroxide. The molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol. Therefore, 37 grams of calcium hydroxide is equal to 0.499 moles.
