0.1 M HCl
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Diluting a 0.01N HCl solution ten times would result in a 0.001N HCl solution. Since HCl is a strong acid that fully dissociates in water, the pH of a 0.001N HCl solution would be around 3 (pH = -log[H+]).
The pH of a 6M HCl solution is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a solution containing 6M HCl is 0.
The pH of water decreases after adding HCl due to the increase in hydrogen ions. The resulting pH level depends on the amount of HCl added.
To find the pH of a 0.03 N solution of HCl, we first recognize that HCl is a strong acid that dissociates completely in solution. Since the normality (N) of HCl is equal to its molarity (M) for monoprotic acids, a 0.03 N solution corresponds to a concentration of 0.03 M. The pH can be calculated using the formula pH = -log[H⁺], so pH = -log(0.03) ≈ 1.52.
Diluting a 0.01N HCl solution ten times would result in a 0.001N HCl solution. Since HCl is a strong acid that fully dissociates in water, the pH of a 0.001N HCl solution would be around 3 (pH = -log[H+]).
The pH of a 6M HCl solution is 0.
- log(0.00450 M HCl)= 2.3 pH=======
The pH of a solution containing 6M HCl is 0.
The pH of water decreases after adding HCl due to the increase in hydrogen ions. The resulting pH level depends on the amount of HCl added.
.260 M of HCL, not 260 More than likely correct, but, - log(0.260 M HCl) = 0.6 pH ----------- ( pH can be below 1 )
A 0.1 M concentration of HCl corresponds to a pH of 1.0.
The pH increases because the HCl is becoming less acidic. A pH of 7 is neutral. A pH falls below 7, acidity increases. As pH rises above 7, basicity increases. Diluting HCl means that the HCl becomes less concentrated, and therefore, less acidic. As it becomes less acidic, the pH will become more basic, and thus increase.
The pH of a 0.25 M HCl solution is approximately 0.60. This is because HCl is a strong acid that dissociates completely in water to form H+ ions, resulting in a high concentration of H+ ions and a low pH.
Since HCl is a strong acid it completely dissociates. Therefore [H+] = [HCl] and this case = 0.25 M. pH = -log [H+] = 0.602
The pH of a 0.005N HCl solution is approximately 2.3. This is because HCl is a strong acid that dissociates completely in water to form H+ ions, leading to an acidic pH.