0
1.0 mole NaOH / kg water = 1.0 molal NaOH
The conversions of molality, b, to and from the molarity , c,
for one-solute solutions are:
c = ρ.b / [1 + b.M]
and
b = c / [ρ -c.M]
where ρ is the mass density of the solution, b is the molality, and M is the molar mass of the solute.
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What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg?
The molality is 0,2.
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
0.33 mol/kg (apex)
Which is more concentrated 1molarity of NaOH or 1molality of NaOH?
The conversions of molality, b, to and from the molarity , c,for one-solute solutions are:c = ρ.b / [1 + b.M]andb = c / [ρ -c.M]where ρ is the mass density of the solution, b is the molality, and M is the molar mass of the solute.
What is the molality of a solution made by dissolving 2 moles of NaOH in 6kg of water?
0.33 mol/kg
What is the molality of a solution made by dissolving 2 mole of NaOH in 6kg of water?
0.33 mol/kg
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg?
The molality is 0,2.
What is the molality of a substance made by dissolving 2 moles of NaOH in 10 kg of water?
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
0.33 mol/kg (apex)
Which is more concentrated 1molarity of NaOH or 1molality of NaOH?
The conversions of molality, b, to and from the molarity , c,for one-solute solutions are:c = ρ.b / [1 + b.M]andb = c / [ρ -c.M]where ρ is the mass density of the solution, b is the molality, and M is the molar mass of the solute.
What is the molality of a solution made by dissolving 2 mole of NaOH in 6kg of water?
0.33 mol/kg
What is the molality of a solution made by dissolving 2 moles of NaOH in 6kg of water?
0.33 mol/kg
What is the molality of a solution made by dissolving two moles of NaOH in 6 kg of water?
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
What is the molality of a solution made by a dissolving 2 moles of naoh in 6 kg of water?
0.33 mol/kg (apex)
What is the Amount of benzoic acid to be neutralized by 20 mL NaOH solution in both moles and grams?
We need to know the Molarity (or Molality or formality) of both the acid and the NaOH solution in order to answer this question.
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg?
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
