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Apparently BromPhenol Blue ionization is a two-step process: BH2 BH- + H+ BH- B-2 + H+ (pKa ~ 3.5 - 4.0) The neutral form, whose formula is given in the wikipedia article http://en.wikipedia.org/wiki/Bromphenol_blue , is a strong acid, I haven't seen any estimate of the pKa. The yellow-blue transition which is used as a pH indicator would then be due to the transition from the monoanionic form (yellow) to the dianionic form. The structure of the monoanionic form is given in Scheme 1 of the article: (P.M. Saikia, A. Kalita, B. Gohain, S. Sarma and R.K. Dutta, Colloids Surf. A 216 (2003), p. 21.). Its formation appears to involve ionization of one phenolic OH followed by enol-keto transition with double-bond formation to the central carbon, displacing the sulfonic adduct to that atom. The dianionic form is presumably the same, but with the remaining phenolic OH ionized.

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