PbI2 is commonly known as Lead(II) Iodide. It is also sometimes called plumbous iodide from the Latin root plumbum, which means lead.
Lead(II) iodide (PbI2) is typically a yellow colored solid.
This compound is lead iodide.
Formula: PbI2
PbI2 has TWO(2) elements. They are ;- Pb ; Lead (Plumbum ; Latin) I ; Iodine . However, there are three (3) atoms in PbI2. Viz: - 1 x Pb(Lead) 2 x I (iodine) 1 + 2 = 3 The name of the sibstance is 'lead iodide'.
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
Lead(II) iodide (PbI2) is typically a yellow colored solid.
This compound is lead iodide.
Formula: PbI2
PbI2 has TWO(2) elements. They are ;- Pb ; Lead (Plumbum ; Latin) I ; Iodine . However, there are three (3) atoms in PbI2. Viz: - 1 x Pb(Lead) 2 x I (iodine) 1 + 2 = 3 The name of the sibstance is 'lead iodide'.
The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.
PBI2, or lead(II) iodide, consists of one lead (Pb) atom and two iodine (I) atoms. Therefore, there are a total of three atoms in one formula unit of PBI2.
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced equation for lead iodide is: PbI2 (s) ↔ Pb2+ (aq) + 2I- (aq)
Formula: PbI2
PbI2
It would be: PbI2
Formula: PbI2