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Number of moles= Mass/molar mass (g/mol)
Hence Mass= mol × molar mass
Mol=2.55
Molar mass of KMnO4= 39+55+(16×4)= 158g/mol
Where K=39, Mn=55 and O =16
Hence Mass of KMnO4 in 2.55 mols of the compound= 2.55×158= 402.9g.
What else can I help you with?
How many mols in 100g of KMnO4?
0.006327754
How many moles are in 100g of KMnO4?
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
If you have 17.34 moles of potassium permanganate how many kilograms of the substance do you have?
Potassium permanganate = KMnO4 Molar mass of KMnO4 K = 1 * 39.10 g = 39.10 g Mn = 1 * 54.94 g = 54.94 g O = 4 * 16.00 g = 64.00 g Total = 158.04 g/mol 17.34 mol KMnO4 * (158.04 g/1 mol KMnO4) = 2740.41 g KMnO4 Convert the grams to kilograms. 1 kg = 1000 g 2740.41 g * (1 kg/1000 g) = 2.74041 kg Therefore, 17.34 moles of potassium permanganate is equal to about 2.74 kilograms.
What is the percent composition of KMnO4?
Potassium permanganate, or KMnO4, has a molar mass of 158g/mol. (39+55+16x4). % composition of K: 39/158=0.247=24.7%. % composition of Mn: 55/158=0.348=34.8%. % composition O: 64/158=0.405=40.5%.
How do you find molar concentration of chemical compounds?
By applying the formula: No. of moles = Mass of compound / Molar Mass of compound eg: We have to find concentration of KMnO4,so ; No.of moles of KMno4 = Mass of KMnO4 / Molar mass of KMnO4
How many mols in 100g of KMnO4?
0.006327754
How many moles are in 100g of KMnO4?
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
How many grams of potassium permanganate KMnO4 are in 2.55 moles?
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
If you have 17.34 moles of potassium permanganate how many kilograms of the substance do you have?
Potassium permanganate = KMnO4 Molar mass of KMnO4 K = 1 * 39.10 g = 39.10 g Mn = 1 * 54.94 g = 54.94 g O = 4 * 16.00 g = 64.00 g Total = 158.04 g/mol 17.34 mol KMnO4 * (158.04 g/1 mol KMnO4) = 2740.41 g KMnO4 Convert the grams to kilograms. 1 kg = 1000 g 2740.41 g * (1 kg/1000 g) = 2.74041 kg Therefore, 17.34 moles of potassium permanganate is equal to about 2.74 kilograms.
How many grams of potassium permanganate are in 2.20 moles?
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
What are the formula molar mass and color of potassium permanganate?
molar mass is 158.03 g/mol color is purple chemical formula is KMnO4
What is the percent composition of KMnO4?
Potassium permanganate, or KMnO4, has a molar mass of 158g/mol. (39+55+16x4). % composition of K: 39/158=0.247=24.7%. % composition of Mn: 55/158=0.348=34.8%. % composition O: 64/158=0.405=40.5%.
How do you find molar concentration of chemical compounds?
By applying the formula: No. of moles = Mass of compound / Molar Mass of compound eg: We have to find concentration of KMnO4,so ; No.of moles of KMno4 = Mass of KMnO4 / Molar mass of KMnO4
Molar mass of potassium permanganate?
A gram is a unit of measurement, concerning how much mass, that is, how much of something there is. You would have to weight it (or mass it) on a scale to find out.
How many grams KMnO4 take in 0.1N KMnO4 solution?
(158 g = 1 mole) --- molar mass of potassium permanganate. You also need to specify the volume to be made. For 1 liter just add 15.8 g in a volumetric flask to make 1000 ml (1 liter) of solution.
How do you prapare 0.01 m potassium permanganate?
To prepare a 0.01 M solution of potassium permanganate (KMnO4), first calculate the amount needed by using the formula: mass (g) = molarity (mol/L) × volume (L) × molar mass (g/mol). The molar mass of KMnO4 is approximately 158.04 g/mol, so for 1 liter of solution, you would need 1.58 grams of KMnO4. Dissolve this amount in a small volume of distilled water, then transfer the solution to a 1-liter volumetric flask and dilute to the mark with distilled water. Mix thoroughly to ensure complete dissolution.
What mass of KMnO4 is required to prepare 3.00 liters of a 0.05253 M solution of KMnO4?
To find the mass of KMnO4 needed, you can use the formula: mass = molarity x volume x molar mass. First, calculate the moles of KMnO4 using moles = molarity x volume. Then, multiply the moles by the molar mass of KMnO4 to find the mass needed.
