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Number of moles= Mass/molar mass (g/mol)
Hence Mass= mol × molar mass
Mol=2.55
Molar mass of KMnO4= 39+55+(16×4)= 158g/mol
Where K=39, Mn=55 and O =16
Hence Mass of KMnO4 in 2.55 mols of the compound= 2.55×158= 402.9g.
Michael Akachukwu
Wiki User
∙ 11y ago1 mole KMnO4 = 149.032g KMnO4
2.55mol KMnO4 x 149.032g KMnO4/mol KMnO4 = 380.0316g KMnO4 = 3.80 x 102g KMnO4, rounded to three significant figures.
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How do you find molar concentration of chemical compounds?
The Stoichiometry of molar concentration follows this simple formula: Mol = Volume (dm³) × Molar Concentration (mol/dm³) Hence: Molar Concentration (mol/dm³) = Number of moles (mol)/ Volume (dm³)
How many moles are in 100g of KMnO4?
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
If you have 17.34 moles of potassium permanganate how many kilograms of the substance do you have?
Potassium permanganate = KMnO4 Molar mass of KMnO4 K = 1 * 39.10 g = 39.10 g Mn = 1 * 54.94 g = 54.94 g O = 4 * 16.00 g = 64.00 g Total = 158.04 g/mol 17.34 mol KMnO4 * (158.04 g/1 mol KMnO4) = 2740.41 g KMnO4 Convert the grams to kilograms. 1 kg = 1000 g 2740.41 g * (1 kg/1000 g) = 2.74041 kg Therefore, 17.34 moles of potassium permanganate is equal to about 2.74 kilograms.
What is the molarity of 0.1 normal KMnO4?
The formula mass of KMnO4 is 158.0Amount of KMnO4 = mass of sample / molar mass = 100/158.0 = 0.633 molThere are 0.633 moles in 100g of potassium permanganate.
What is the equivalent weight of potassium chromate What is the equivalent weight of KMnO4 in neutral medium?
31.608 g/mol
How do you find molar concentration of chemical compounds?
The Stoichiometry of molar concentration follows this simple formula: Mol = Volume (dm³) × Molar Concentration (mol/dm³) Hence: Molar Concentration (mol/dm³) = Number of moles (mol)/ Volume (dm³)
What are the formula molar mass and color of potassium permanganate?
molar mass is 158.03 g/mol color is purple chemical formula is KMnO4
How many moles are in 100g of KMnO4?
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
How many grams of potassium permanganate KMnO4 are in 2.55 moles?
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
If you have 17.34 moles of potassium permanganate how many kilograms of the substance do you have?
Potassium permanganate = KMnO4 Molar mass of KMnO4 K = 1 * 39.10 g = 39.10 g Mn = 1 * 54.94 g = 54.94 g O = 4 * 16.00 g = 64.00 g Total = 158.04 g/mol 17.34 mol KMnO4 * (158.04 g/1 mol KMnO4) = 2740.41 g KMnO4 Convert the grams to kilograms. 1 kg = 1000 g 2740.41 g * (1 kg/1000 g) = 2.74041 kg Therefore, 17.34 moles of potassium permanganate is equal to about 2.74 kilograms.
Calculate the molarity of a solution of potassium permanganate and density is 1.04 gmL which contans 15.00 percent by mass?
C [mol/L] = w% * rho [g/mL] *1000 [mL/L] / (100% * M [g/mol] ) = = w% * rho [g/mL] *10 [mL/L%] / ( M [g/mol] ) = = 15.00 % * 1.04 [g/mL] *10 [mL/L%] / ( 158.034 [g/mol] ) = = 0.987 [mol/L] the molarity of the solution of potassium [in mol per liter] equals the content of KMnO4 by mass in percents multiply by density in g/mL multiply by 10 [mL/(L*%)] divide by molar mass of KMnO4 (M = 158.034 g/mol) This gives 0.987 mol/L. Thus the molarity equals approximately 1 M.
What is the molarity of 0.1 normal KMnO4?
The formula mass of KMnO4 is 158.0Amount of KMnO4 = mass of sample / molar mass = 100/158.0 = 0.633 molThere are 0.633 moles in 100g of potassium permanganate.
What is the Equivalent weight of KMnO4 in different medium?
The oxidation state of 'Mn' in KMnO4 is +7 after reaction as oxidizing agent 'Mn; becomes +2 so change in oxidation number is '5' the formula mass divided by change in oxidation number is equal to equivalent mass or weight, 158/5 = 31.7
What mass of KMnO4 is required to prepare 3.00 liters of a 0.05253 M solution of KMnO4?
24 g
What is the equivalent weight of potassium chromate What is the equivalent weight of KMnO4 in neutral medium?
31.608 g/mol
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the percent composition of KMnO4?
Potassium permanganate, or KMnO4, has a molar mass of 158g/mol. (39+55+16x4). % composition of K: 39/158=0.247=24.7%. % composition of Mn: 55/158=0.348=34.8%. % composition O: 64/158=0.405=40.5%.
