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What mass of ironIIInitrate is needed for a chemical reaction that requires 6.00 moles of FeNO33?
To determine the mass of iron(II) nitrate needed for 6.00 moles of Fe(NO3)2, you first need to calculate the molar mass of Fe(NO3)2. Fe(NO3)2 has a molar mass of approximately 179.86 g/mol. Therefore, the mass needed would be 6.00 moles * 179.86 g/mol ≈ 1079.16 grams of Fe(NO3)2.
How many grams of CrNO33 are required to prepare 500.0 mL of an aqueous solution which has a Cr3 concentration of 2.08 M?
To determine the grams of Cr(NO3)3 needed, first calculate the molar mass of Cr(NO3)3. Then, use the formula: moles = Molarity x Volume (in L) to find the moles of Cr(NO3)3. Finally, multiply the moles by the molar mass to get the grams.
How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
How many grams of Cu(NO3)2 will be produced if you start with 4.2 grams of cu?
To determine the number of grams of Cu(NO3)2 produced, you need to consider the molar ratio between Cu(NO3)2 and Cu. Firstly, convert the 4.2 grams of Cu to moles using the molar mass of Cu. Then, use the balanced chemical equation to find the moles of Cu(NO3)2 produced. Finally, convert the moles of Cu(NO3)2 to grams using its molar mass.
How many grams of ca(no3) are needed to make a 250 ml of 0.50M solution?
To calculate the amount of Ca(NO3)2 needed for a 0.50M solution: Find the molar mass of Ca(NO3)2 = 164.09 g/mol. Calculate the number of moles needed: 0.50 moles/L x 0.250 L = 0.125 moles. Convert moles to grams: 0.125 moles x 164.09 g/mol ≈ 20.51 grams of Ca(NO3)2 are needed.
How many moles are in 16.4 g of Ca(NO3)2?
To find the number of moles in 16.4 g of calcium nitrate, Ca(NO3)2, you first need to calculate its molar mass. The molar mass of Ca(NO3)2 is approximately 164.1 g/mol. Using the formula for moles (moles = mass / molar mass), you can calculate the moles: ( \text{moles} = \frac{16.4 , \text{g}}{164.1 , \text{g/mol}} \approx 0.100 , \text{moles} ). Therefore, there are about 0.100 moles of Ca(NO3)2 in 16.4 g.
How do you Convert 8.50 grams HgNO32 to moles?
For this you need the atomic (molecular) mass of Hg(NO3)2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Hg(NO3)2=324.6 grams8.50 grams Hg(NO3)2 / (324.6 grams) = .0262 moles Hg(NO3)2
What mass of ironIIInitrate is needed for a chemical reaction that requires 6.00 moles of FeNO33?
To determine the mass of iron(II) nitrate needed for 6.00 moles of Fe(NO3)2, you first need to calculate the molar mass of Fe(NO3)2. Fe(NO3)2 has a molar mass of approximately 179.86 g/mol. Therefore, the mass needed would be 6.00 moles * 179.86 g/mol ≈ 1079.16 grams of Fe(NO3)2.
How many grams of CrNO33 are required to prepare 500.0 mL of an aqueous solution which has a Cr3 concentration of 2.08 M?
To determine the grams of Cr(NO3)3 needed, first calculate the molar mass of Cr(NO3)3. Then, use the formula: moles = Molarity x Volume (in L) to find the moles of Cr(NO3)3. Finally, multiply the moles by the molar mass to get the grams.
How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
What is the number of moles in 132g Ba NO3 2?
Ba(NO3)2The total mass for this molecule is 261gso what is 261g/132g this is 1.97moles
How many moles of nitrate ion are present in 5.600grams of calcium nitrate?
To find the number of moles of nitrate ion in calcium nitrate, first calculate the molar mass of calcium nitrate (Ca(NO3)2). This is 164.09 g/mol. Divide the given mass (5.600 g) by the molar mass to get the number of moles, which is 0.034 moles. Since there are two nitrate ions in one calcium nitrate molecule, multiply the number of moles by 2 to get the number of moles of nitrate ions, which is 0.068 moles.
How many grams of Cu(NO3)2 will be produced if you start with 4.2 grams of cu?
To determine the number of grams of Cu(NO3)2 produced, you need to consider the molar ratio between Cu(NO3)2 and Cu. Firstly, convert the 4.2 grams of Cu to moles using the molar mass of Cu. Then, use the balanced chemical equation to find the moles of Cu(NO3)2 produced. Finally, convert the moles of Cu(NO3)2 to grams using its molar mass.
How many grams of ca(no3) are needed to make a 250 ml of 0.50M solution?
To calculate the amount of Ca(NO3)2 needed for a 0.50M solution: Find the molar mass of Ca(NO3)2 = 164.09 g/mol. Calculate the number of moles needed: 0.50 moles/L x 0.250 L = 0.125 moles. Convert moles to grams: 0.125 moles x 164.09 g/mol ≈ 20.51 grams of Ca(NO3)2 are needed.
How many molecules are there in 122 grams of Cu NO3 2?
To determine the number of molecules in 122 grams of Cu(NO3)2, you need to first calculate the number of moles of Cu(NO3)2 using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23) to convert the moles of Cu(NO3)2 to molecules.
How many moles of nitrate are there in 2.0 moles of Fe(NO3)3?
6 moles
How many moles of ironIII hydroxide are needed to react with excess nitric acid to produce 63.8 g ironIII nitrate?
Balanced equation. Fe(OH)3 + 3HNO3 --> Fe(NO3)3 + 3H2O 63.8 grams Fe(NO3)3 (1 mole Fe(NO3)3/241.88 grams)(1 mole Fe(OH)3/1 mole Fe(NO3)3 = 0.264 moles iron III hydroxide needed ==========================
