Na + O + H = ?
22.99 +16.00+1.01= 40
this is easily found with any compound, just add their molar masses up. If there are elements that are present which you have more than one of just multiply its mass by that number.
22.997 + 16.0 + 1.008 = 40.005 = molecular weight of NaOH
Molar mass of Sodium oxide (Na2O) is 61.9789 g/mol
the mass of 1 mole of NaOH is 40 grams
39.9971 grams per mole
40 grams
Molar mass of NaOH is 39.998 grams. So, 2.75 mol NaOH (39.998g NaOH/1 mol NaOH) = 109.9945 grams NaOH ( you do the sigi figi )
mass divided by molar mass gives moles: 20 g NaOH / 40 g.mol-1 = 0.5 mol NaOH
Need total molar mass sodium hydroxide which you can easily get from your periodic table. 2.2 moles NaOH (39.998 grams/1 mole NaOH) = 88 grams in mass ==============
The molar mass remain the same but because the NaOH solution absorb carbon dioxide the titer of this standardized solution was altered.
One liter of a one molar solution of NaOH in water contains 40g of NaOH. The quantity must be known.
Molar mass of NaOH is 39.998 grams. So, 2.75 mol NaOH (39.998g NaOH/1 mol NaOH) = 109.9945 grams NaOH ( you do the sigi figi )
mass divided by molar mass gives moles: 20 g NaOH / 40 g.mol-1 = 0.5 mol NaOH
Need total molar mass sodium hydroxide which you can easily get from your periodic table. 2.2 moles NaOH (39.998 grams/1 mole NaOH) = 88 grams in mass ==============
The molar mass remain the same but because the NaOH solution absorb carbon dioxide the titer of this standardized solution was altered.
One liter of a one molar solution of NaOH in water contains 40g of NaOH. The quantity must be known.
The molar mass of NaOH is 39.9 g/mol, so if you multiply is by 2.5, you get the answer. 99.75 g/mol
No, it's not correct. Liters*molarity = moles (0.015L)*(1.600moles/L) = 0.024 moles of NaOH One mole of NaOH would neutralize one mole of the MONOprotic acid, so: (0.024 moles of acid)/(0.020L) = 1.2M
Given that 200cm3 yieded 20g.therefore 22400cm3 which is the volume occupied by gas at s.t.p will contained:(22400cm3 times 20g) divided by 200cm3,which equals 2240g.but molarity is mass conc./molar mass,here molar mass of NaOH is 40.Hence the molarity is:2240/40 which equals to 56moles/g.
First write balance equation 2Na + 2H2O --> 2NaOH + H2 molar mass Na = 22.99 g/mol molar mass H2O = 18.02 g/mol molar mass NaOH = 40.0 g/mol Determine limiting reagent. 1.20 g Na * 1mol Na/22.99g Na = 0.05219 (0.0522) mol Na Since 2Na = 2NaOH in balanced equation, The mol of NaOH is also 0.0522 3ml h20 = 3 gram h20 (1ml^3=1g^3) 3g H20 * 1mol/18gH20 = 0.167 (0.17) mol H20 So .17 ml H20 equals .17 mol NaOH and .0522 mole Na equals .0522 mol NaOH The smaller one is the limiting reagent, which in this case is Na 0.0522mol NaOH*40g NaOH/1mol NaOH = 2.09 gram NaOH
The molar mass of sulfur is 32.065. Molar mass is the mass per mole of a substance. In other words, Molar Mass = Mass/Amount of Substance.
molacular mass
Molar Mass of Carbon + Molar Mass of Silicon = Molar Mass of SiC. 12.0107 + 28.0855 = 40.0962 g / mol.