Na + O + H = ?
22.99 +16.00+1.01= 40
this is easily found with any compound, just add their molar masses up. If there are elements that are present which you have more than one of just multiply its mass by that number.
The molar mass of NaOH (sodium hydroxide) is approximately 40 g/mol.
To find the number of moles in 12.0 g of NaOH, you first need to calculate its molar mass. The molar mass of NaOH (sodium hydroxide) is 39.997 g/mol. Next, you divide the given mass by the molar mass: 12.0 g / 39.997 g/mol ≈ 0.30 moles of NaOH.
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
The molar mass of NaOH is 40 g/mol. The molar mass of sodium is 23 g/mol. Therefore, the percent by mass of sodium in NaOH is (23 g/mol / 40 g/mol) x 100% = 57.5%.
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
The molar mass of NaOH (sodium hydroxide) is approximately 40 g/mol.
To find the number of moles in 12.0 g of NaOH, you first need to calculate its molar mass. The molar mass of NaOH (sodium hydroxide) is 39.997 g/mol. Next, you divide the given mass by the molar mass: 12.0 g / 39.997 g/mol ≈ 0.30 moles of NaOH.
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
The molar mass of NaOH is 40 g/mol. The molar mass of sodium is 23 g/mol. Therefore, the percent by mass of sodium in NaOH is (23 g/mol / 40 g/mol) x 100% = 57.5%.
The molarity of NaOH solution is 0.010 mol/L. To find the mass, you need to multiply the molarity by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol. Therefore, the mass of NaOH in 2.5 L of 0.010 M solution is 1 g.
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
To find the number of moles of NaOH in a 36.65g sample, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is 40g/mol (sodium 22.99g/mol + oxygen 16.00g/mol + hydrogen 1.01g/mol). So, 36.65g ÷ 40g/mol = 0.9163 moles of NaOH.
To convert grams of NaOH to moles, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). Thus, 20 grams of NaOH is equivalent to 0.5 moles (20 g / 40 g/mol).
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
To determine the number of moles in 4g of sodium hydroxide (NaOH), divide the mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40g/mol (Na = 23g/mol, O = 16g/mol, H = 1g/mol). Therefore, 4g of NaOH is equal to 0.1 moles.
To find the number of moles in 80.0g of NaOH, divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40.0 g/mol (sodium - 22.99 g/mol, oxygen - 16.00 g/mol, hydrogen - 1.01 g/mol). Therefore, there are 2.00 moles of NaOH in 80.0g.
To calculate the mass of 2.5 moles of sodium hydroxide (NaOH), you need to know the molar mass of NaOH, which is 40 g/mol. Multiply the number of moles by the molar mass: 2.5 moles x 40 g/mol = 100 grams of sodium hydroxide.