Scandium carbonate, Sc2(CO3)3. x H2O; molecular mass is 296,96.
Ga2(CO3)3 -> Ga2O3 + 3CO2 Gallium (III) Carbonate and Gallium Oxide are equimolar so 55 moles of gallium carbonate must be used. The Molar Mass of Gallium (III) Carbonate is about 319 g/mol 319 g/mol (55 mols) = 17,545 g
The molar mass of lead(III) phosphate (Pb3(PO4)2) can be calculated by adding the molar mass of lead (Pb) and the molar mass of phosphate (PO4) in the compound. The molar mass of Pb is 207.2 g/mol and the molar mass of PO4 is 94.97 g/mol. Therefore, the molar mass of Pb3(PO4)2 is 3(207.2) + 2(94.97) = 611.54 g/mol.
Only a few elements can be chemically combined with scandium. Here are a few examples of chemical reactions involving Scandium;Scandium + Chlorine --> Scandium (III) ChlorideScandium + Nitrogen --> Scandium (III) NitrateScandium + Sulphur --> Scandium (III) SulphideScandium + Oxygen --> Scandium (III) Oxide
The iodate anion is IO3^-. Scandium is Sc and as III is is Sc^3+. So scandium(III) iodate would be Sc(IO3)3
The molar mass of AuCl3 (gold(III) chloride) is calculated by adding the atomic mass of gold (Au) and three times the atomic mass of chlorine (Cl). The molar mass of AuCl3 is approximately 303.32 g/mol.
The molar mass of Iron(III) carbonate (Fe2(CO3)3) is calculated by adding the molar mass of iron (Fe) and three times the molar mass of carbonate (CO3). The molar mass of iron is approximately 55.85 g/mol, and the molar mass of carbonate is 60.01 g/mol. Therefore, the molar mass of Iron(III) carbonate is 291.88 g/mol.
Ga2(CO3)3 -> Ga2O3 + 3CO2 Gallium (III) Carbonate and Gallium Oxide are equimolar so 55 moles of gallium carbonate must be used. The Molar Mass of Gallium (III) Carbonate is about 319 g/mol 319 g/mol (55 mols) = 17,545 g
To find the mass of chromium in 283 kg of chromium(III) carbonate (Cr2(CO3)3), we first determine the molar mass of the compound. The molar mass of chromium(III) carbonate is approximately 194.19 g/mol, which contains 2 chromium atoms (about 52.00 g/mol each). Thus, the total mass of chromium in the compound is about 104.00 g/mol. Using the proportion of chromium in the compound, the mass of chromium in 283 kg of chromium(III) carbonate can be calculated as follows: [ \text{Mass of chromium} = \left(\frac{104.00 \text{ g/mol}}{194.19 \text{ g/mol}}\right) \times 283,000 \text{ g} \approx 147,000 \text{ g} \text{ or } 147 \text{ kg}. ] Therefore, there are approximately 147 kg of chromium in 283 kg of chromium(III) carbonate.
The molar mass of lead(III) phosphate (Pb3(PO4)2) can be calculated by adding the molar mass of lead (Pb) and the molar mass of phosphate (PO4) in the compound. The molar mass of Pb is 207.2 g/mol and the molar mass of PO4 is 94.97 g/mol. Therefore, the molar mass of Pb3(PO4)2 is 3(207.2) + 2(94.97) = 611.54 g/mol.
Only a few elements can be chemically combined with scandium. Here are a few examples of chemical reactions involving Scandium;Scandium + Chlorine --> Scandium (III) ChlorideScandium + Nitrogen --> Scandium (III) NitrateScandium + Sulphur --> Scandium (III) SulphideScandium + Oxygen --> Scandium (III) Oxide
Scandium (III) oxide
The iodate anion is IO3^-. Scandium is Sc and as III is is Sc^3+. So scandium(III) iodate would be Sc(IO3)3
The molar mass of AuCl3 (gold(III) chloride) is calculated by adding the atomic mass of gold (Au) and three times the atomic mass of chlorine (Cl). The molar mass of AuCl3 is approximately 303.32 g/mol.
The formula for scandium III selenide is Sc2Se3. This compound consists of two scandium ions (Sc3+) and three selenide ions (Se2-).
To calculate the percent composition by mass of iron in iron (III) chloride (FeCl₃), first determine its molar mass. The molar mass of Fe is approximately 55.85 g/mol, and for Cl, it is about 35.45 g/mol, giving FeCl₃ a total molar mass of approximately 162.2 g/mol (55.85 + 3 × 35.45). The percent composition of iron is then calculated as (mass of Fe / molar mass of FeCl₃) × 100, which is (55.85 / 162.2) × 100 ≈ 34.4%. Thus, the percent composition by mass of iron in iron (III) chloride is approximately 34.4%.
Scandium chloride (or scandium trichloride), ScCl3
To find the mass of 1.40 mol of iron (III) sulfate (Fe2(SO4)3), you need to calculate the molar mass of the compound. Iron (III) sulfate has a molar mass of approximately 399.9 g/mol. Therefore, the mass of 1.40 mol of iron (III) sulfate would be 1.40 mol x 399.9 g/mol = 559.86 grams.