0
What else can I help you with?
How many molecules are in 325g of CBr4?
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.
What is the oxidation number for Ca in Ca Br?
The molecular formula should be CBr4. The oxidation numbers are -1 for each Br, +4 for C.
How many molecules are in 334 g CBr4?
To calculate the number of molecules in 334 g of CBr4, you need to first convert the mass to moles using the molar mass of CBr4 (331.6 g/mol). Once you have the moles, you can then use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in 334 g of CBr4.
What is the oxidation number of acetate?
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
What is the oxidation number of H2CO2?
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
How many molecules are in 325g of CBr4?
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.
What is the oxidation number for Ca in Ca Br?
The molecular formula should be CBr4. The oxidation numbers are -1 for each Br, +4 for C.
How many molecules are in 393g of CBr4?
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
How many molecules are in 334 g CBr4?
To calculate the number of molecules in 334 g of CBr4, you need to first convert the mass to moles using the molar mass of CBr4 (331.6 g/mol). Once you have the moles, you can then use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in 334 g of CBr4.
What is the symbol for CBr4?
CBr4 , this is the correct formula for carbon-tetra-bromide
What is the oxidation number of HClO?
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
How many ATOMS of carbon are present in 4.25 moles of carbon tetrabromide?
There are 1.03 x 10^24 atoms of carbon in 4.25 moles of carbon tetrabromide (CBr4). This can be calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of carbon in CBr4 (4).
What is the oxidation number of acetate?
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
What is the oxidation number of H2CO2?
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
What is the Oxidation number of sand?
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
What is the oxidation number of nitrosyl?
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
What is the oxidation number for Nb in NbO2?
Oxidation number of Nb is +4. Oxidation number of O is -2.
