-1 for each Br and +4 for C
The molecular formula should be CBr4. The oxidation numbers are -1 for each Br, +4 for C.
oxidation number of I is -1. oxidation number of F is +1.
325 g of CBr4 have 5,9.10e23 molecules.
Zn has oxidation number +2; S has oxidation number -2
The oxidation number for H is +1, and the oxidation number for O is -1.
The molecular formula should be CBr4. The oxidation numbers are -1 for each Br, +4 for C.
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
oxidation number of I is -1. oxidation number of F is +1.
CBr4 , this is the correct formula for carbon-tetra-bromide
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
325 g of CBr4 have 5,9.10e23 molecules.
Zn has oxidation number +2; S has oxidation number -2
The oxidation number for H is +1, and the oxidation number for O is -1.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
Oxidation number of Si is +4.Oxidation number of O is -2.
Carbon atoms oxidation number is +2.Hydrogen's oxidation number is +1.Oxygen's oxidation number is -2.
Potassium's oxidation number is +1. Chromium's oxidation number is +6. Oxygen's oxidation number is -2.