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Use the ideal gas law, expressed by the equation PV=nRT. The pressure, P, is 99.2 kPa. The temperature, T, is 45.0 degrees Celsius, which you must first convert to Kelvins by adding 273. The number of moles, n, is given as 0.55. The ideal gas constant, R, is approximately 8.3. Now, solve for volume, V:

99.2(V)=0.55(8.3)(45.0+273)

99.2(V)=1,451.67; V = 14.64 liters.

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10y ago
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8y ago

Use the combined gas law, PV = nRT

P = 10.634 atm

V = ?

n = 0.56 moles

R = gas constant = 0.0821 L-atm/deg-mole

T = 65ºC +273 = 338ºK

V = nRT/P = (0.56)(0.0821)(338)/10.634 atm

V = 1.46 liters = 1.5 liters (2 sig figs)

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11y ago

PV = nRT

P = Pressure (Pascals)

V = Volume

n = Number of Moles

R = Ideal Gas Constant

T = Temperature (K)

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9y ago

One mole takes 22.4l at STP.So 2.66mol takes a volume of 59.584l

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7y ago

The volume occupied by 2,50 moles of gas at 98,5 psi and 98,5 degrees F is 9,49 L.

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7y ago

The volume is 125,066 litres.

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7y ago

0,069 moles of gas

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Q: What is the volume of .56 moles of gas at 10.634 ATM and 65 c?
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