The molar volume of hydrogen is approx. 22,7 L at 100 kPa and 0C.
The molar volume of hydrogen gas at STP (Standard Temperature and Pressure) is 22.4 liters per mole.
At standard temperature and pressure (STP), the gas that occupies the highest volume is hydrogen.
To calculate the volume of hydrogen produced at STP when 13.49g of aluminum reacts with sulfuric acid, you first need to determine the moles of aluminum and then use the balanced chemical equation to find the moles of hydrogen produced. Finally, you can use the ideal gas law to calculate the volume of hydrogen. The molar volume of any gas at STP is 22.4 L.
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
At standard temperature and pressure (STP), the volume occupied by 1 mole of any ideal gas is 22.4 liters. Therefore, the volume of 1.42 moles of ammonia at STP would be 1.42 * 22.4 liters = 31.808 liters.
The volume of a gas depends on its pressure, temperature, and volume according to the ideal gas law PV = nRT. Without knowing the pressure, temperature, or container size, it's not possible to determine the volume occupied by the 0.48 moles of hydrogen.
The molar volume of hydrogen gas at STP (Standard Temperature and Pressure) is 22.4 liters per mole.
At standard temperature and pressure (STP), the gas that occupies the highest volume is hydrogen.
To calculate the volume of hydrogen produced at STP when 13.49g of aluminum reacts with sulfuric acid, you first need to determine the moles of aluminum and then use the balanced chemical equation to find the moles of hydrogen produced. Finally, you can use the ideal gas law to calculate the volume of hydrogen. The molar volume of any gas at STP is 22.4 L.
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
At standard temperature and pressure (STP), the volume occupied by 1 mole of any ideal gas is 22.4 liters. Therefore, the volume of 1.42 moles of ammonia at STP would be 1.42 * 22.4 liters = 31.808 liters.
The volume occupied by 0.25 mol of any ideal gas at standard temperature and pressure (STP) is approximately 5.6 L. This is based on the molar volume of an ideal gas at STP, which is around 22.4 L/mol.
To find the volume occupied by 20.4 liters of CO2 at STP (Standard Temperature and Pressure, defined as 0°C and 1 atm), we can use the ideal gas law and the concept of proportionality. At STP, 1 mole of gas occupies 22.4 liters, and 1200 torr is approximately 1.58 atm. Using the combined gas law, we can calculate the volume at STP: [ V_{STP} = V_{initial} \times \frac{P_{initial}}{P_{STP}} \times \frac{T_{STP}}{T_{initial}} ] Substituting the known values, the volume at STP will be approximately 12.9 liters.
The molar volume of a gas at STP is 22.4 liters/mol. The molar mass of hydrogen bromide is 80.9 g/mol. Therefore, the density of hydrogen bromide at STP is 80.9 g/mol / 22.4 L/mol = 3.61 g/L.
This depends on the temperature and the pressure. At standard temperature and pressure 1 mole will occupy 22.4 L, so multiply... 22.4 x 2.22 = 48.728 L at STP.
At STP (Standard Temperature and Pressure), the volume of 1 mole of any gas is 22.4 liters. Since hydrogen gas exists as H2 molecules, 67.2 liters of hydrogen gas at STP contains 3 moles of H2 molecules. Since each H2 molecule contains 2 hydrogen atoms, there are 6 moles of hydrogen atoms, which is equivalent to 6 x 6.022 x 10^23 atoms of hydrogen.