neither a nor b is limiting
The one that runs out first in a reaction - is thoroughly accurate. There are quite a few other limiting reagents in limiting reactions - as well.
To determine the limiting reagent, first write the balanced chemical equation for the reaction. Then, calculate the moles of product that can be formed from each reactant. The reactant that produces the least amount of product is the limiting reagent.
MgCl2 would be the limiting reagent
The limiting reactant or reagent can be determined by calculating the number of moles of each reactant/reagent. Whichever is the lowest number of moles is the limiting reagent in the reaction, assuming that stoichiometry is 1;1
In the reaction between magnesium (Mg) and hydrochloric acid (HCl), the limiting reactant is the reactant that is consumed first, which determines the maximum amount of product that can be formed. To determine the limiting reactant, you would need to compare the moles of magnesium and hydrochloric acid to see which one is present in the lowest stoichiometric amount.
The one that runs out first in a reaction - is thoroughly accurate. There are quite a few other limiting reagents in limiting reactions - as well.
The limiting reagent is the reactant that is completely consumed first in a chemical reaction. To determine the limiting reagent in the reaction between sodium hydroxide and copper chloride, you would need to compare the moles of each reactant present and see which one is in excess and which one is limiting.
When barium sulfate is made, the limiting reagent is the one that is completely consumed in the reaction and determines the amount of product formed. In this case, if barium ions (Ba2+) and sulfate ions (SO42−) are the reactants, the limiting reagent would be the one that is present in lower molar quantity. The one in excess would be the one that is present in higher molar quantity. Without the quantities of each ion provided, it is difficult to determine which is the limiting reagent and which is in excess.
The Limiting Reactant is the smaller number once you compare the two reactants with one product. The product that you are comparing them both with must be the same. The Excess Reactant is the larger number, or the amount left over in the chemical reaction.
To determine the limiting reagent, first write the balanced chemical equation for the reaction. Then, calculate the moles of product that can be formed from each reactant. The reactant that produces the least amount of product is the limiting reagent.
MgCl2 would be the limiting reagent
The limiting reactant or reagent can be determined by calculating the number of moles of each reactant/reagent. Whichever is the lowest number of moles is the limiting reagent in the reaction, assuming that stoichiometry is 1;1
It is impossible a reaction without reactants.
In the reaction between magnesium (Mg) and hydrochloric acid (HCl), the limiting reactant is the reactant that is consumed first, which determines the maximum amount of product that can be formed. To determine the limiting reactant, you would need to compare the moles of magnesium and hydrochloric acid to see which one is present in the lowest stoichiometric amount.
The balanced reaction of cupric iodide and aluminum chloride is 3 CuI2 + 2 AlCl3 = 3 CuCl2 + 2 AlI3. This means that the limiting reaction is cupric iodide, because more of it is required than aluminum chloride.
The reagent needed to complete a reaction depends on the specific reaction being carried out. It could be a catalyst, solvent, substrate, or a specific chemical compound required for the reaction to proceed successfully. Consulting the reaction mechanism or the experimental protocol would help identify the necessary reagents.
To determine the limiting reagent between CuSO₄ and NaOH, we first need to look at the balanced chemical equation for the reaction, which is: [ CuSO₄ + 2 NaOH \rightarrow Cu(OH)₂ + Na₂SO₄ ] According to the stoichiometry, 1 mole of CuSO₄ reacts with 2 moles of NaOH. First, calculate the moles of CuSO₄ and NaOH. Assuming the molar mass of CuSO₄ is approximately 159.61 g/mol, 638.44 g of CuSO₄ corresponds to about 4.00 moles. For 240.0 g of NaOH (molar mass ≈ 40.00 g/mol), this is about 6.00 moles. Since 4.00 moles of CuSO₄ would require 8.00 moles of NaOH but only 6.00 moles are available, NaOH is the limiting reagent.