Strength of bases is related to the ease of accepting a proton which inturn depends on the availability of electron pair on the nitrogen atom (or some other basic atom). More is the availability of electron pair, more easily the proton will be accepted and more will be the basic strength.Aniline is a weaker base than ammonia or cyclohexylamine. It is because of the fact that the electron pair on nitrogen is involved in delocalization, making it less available for donation.
Aniline is more basic than p-nitroaniline because the presence of a nitro group (-NO2) in p-nitroaniline decreases its basicity by withdrawing electron density from the amino group. Aniline, on the other hand, lacks this electron-withdrawing group, making it more basic.
Aniline is less basic than ammonia because the nitrogen lone pair on aniline is partially delocalized into the benzene ring, making it less available to accept a proton. Ammonia, on the other hand, has a more localized lone pair on nitrogen, which is more readily available for protonation.
The dipole moment of chlorobenzene is lower than cyclohexyl chloride because benzene ring in chlorobenzene has resonance delocalization of electrons which reduces the polarity of the molecule, whereas in cyclohexyl chloride, the chlorine atom is directly attached to a saturated carbon atom leading to a more localized dipole moment.
Because the electron withdrawing resonance efect caused by the nitro group on the structure, it makes the electrons pair on the nitrogen less available, if the electron pair is less available it's less basic
Among the compounds listed, aniline is the most basic as it has a lone pair on the nitrogen atom that can readily accept a proton. Benzylamine and p-nitroaniline are less basic due to the presence of electron-withdrawing groups, while acetanilide has a resonance-stabilized amide group that reduces its basicity.
in the case of aniline, the lone pair on nitrogen is involved in resonance with the benzene ring, hence its basicity decreases. no such resonance is seen in cyclohexyl amine, and the lone pair is available to abstract protons and it is stronger base than aniline.
Aniline is more basic than p-nitroaniline because the presence of a nitro group (-NO2) in p-nitroaniline decreases its basicity by withdrawing electron density from the amino group. Aniline, on the other hand, lacks this electron-withdrawing group, making it more basic.
Aniline is less basic than ammonia because the nitrogen lone pair on aniline is partially delocalized into the benzene ring, making it less available to accept a proton. Ammonia, on the other hand, has a more localized lone pair on nitrogen, which is more readily available for protonation.
di-tert butyl ether cannot be made by Williamson's synthesis. why
The dipole moment of chlorobenzene is lower than cyclohexyl chloride because benzene ring in chlorobenzene has resonance delocalization of electrons which reduces the polarity of the molecule, whereas in cyclohexyl chloride, the chlorine atom is directly attached to a saturated carbon atom leading to a more localized dipole moment.
Because the electron withdrawing resonance efect caused by the nitro group on the structure, it makes the electrons pair on the nitrogen less available, if the electron pair is less available it's less basic
Among the compounds listed, aniline is the most basic as it has a lone pair on the nitrogen atom that can readily accept a proton. Benzylamine and p-nitroaniline are less basic due to the presence of electron-withdrawing groups, while acetanilide has a resonance-stabilized amide group that reduces its basicity.
Yes, it is basic in the chemical sense because it contains the amine group -NH2 which can accept a proton.
Aneline is basic,so litmus color is changed into blue
Because in Benzylamine : the unshared lone pair of electron on nitrogen atom isavailable >.. But in n-ethyl aniline: the unshared lone pair of electron is not available and enter resonance with benzene ring .(Villa)
Alkyl groups are slightly electron donating. The methyl groups on the amine in N,N dimethylaniline contribute electron density to the nitrogen lone pair, making it more likely to reach out and grab a proton (ie more basic).
Aniline is a stronger base than o-nitroaniline because the nitro group in o-nitroaniline is electron-withdrawing and decreases its basicity compared to aniline. In basicity trends for amines and anilines, the presence of electron-withdrawing groups decreases basicity.