Pyridine itself (unsubstituted) is basic due to presence of lone pare of electron on nitrogen atom which is not involved in aromatic character , methyl at 4th (Para) position is electron donor due to hyper-conjugation so electrons density at nitrogen becomes increase so 4-methyl pyridine is more basic as compare to unsubstituted pyridine.
In o-aniline phenol Intramolecular hydrogen bonding occurs which is not possible in meta and is responsible for less solubility
in the case of aniline, the lone pair on nitrogen is involved in resonance with the benzene ring, hence its basicity decreases. no such resonance is seen in cyclohexyl amine, and the lone pair is available to abstract protons and it is stronger base than aniline.
Ammonia is more basic than human blood.
Yes, in phenyl hydrazine the electron pair on terminal nitrogen is always available for attack while in analine the electron pair of nitrogen is less available due to involvement in resonance process with benzene ring.
Pyrrole is less basic than pyridine because the lone pair of electrons on the nitrogen in pyrrole is part of the aromatic system and less available for donation compared to the lone pair on the nitrogen in pyridine. This makes pyridine more basic than pyrrole.
Pyridine is more basic than quinoline. This is because the nitrogen atom in pyridine is more readily available to accept a proton compared to the nitrogen in quinoline due to the presence of an additional ring in quinoline which delocalizes the lone pair of electrons on the nitrogen atom, making it less basic.
Pyridine is more basic than pyrrolidine. This is because pyridine has a lone pair of electrons on the nitrogen atom in the aromatic ring, which is more available for donation to accept a proton and act as a base compared to pyrrolidine, which has one of its nitrogen lone pairs delocalized in the aromatic ring.
Aniline is more basic than p-nitroaniline because the presence of a nitro group (-NO2) in p-nitroaniline decreases its basicity by withdrawing electron density from the amino group. Aniline, on the other hand, lacks this electron-withdrawing group, making it more basic.
Strength of bases is related to the ease of accepting a proton which inturn depends on the availability of electron pair on the nitrogen atom (or some other basic atom). More is the availability of electron pair, more easily the proton will be accepted and more will be the basic strength.Aniline is a weaker base than ammonia or cyclohexylamine. It is because of the fact that the electron pair on nitrogen is involved in delocalization, making it less available for donation.
Pyridine itself (unsubstituted) is basic due to presence of lone pare of electron on nitrogen atom which is not involved in aromatic character , methyl at 4th (Para) position is electron donor due to hyper-conjugation so electrons density at nitrogen becomes increase so 4-methyl pyridine is more basic as compare to unsubstituted pyridine.
di-tert butyl ether cannot be made by Williamson's synthesis. why
Pyrrole and pyridine are both aromatic compounds, but they differ in their chemical structures and properties. Pyrrole has a five-membered ring with four carbon atoms and one nitrogen atom, while pyridine has a six-membered ring with five carbon atoms and one nitrogen atom. Pyrrole is more reactive due to its higher electron density, while pyridine is less reactive and more stable. Pyrrole is a stronger base than pyridine because its nitrogen atom is more basic. Additionally, pyrrole is more acidic than pyridine because its nitrogen atom can donate a proton more easily.
Pyridine is less basic than piperidine because the nitrogen in pyridine is part of an aromatic ring, which delocalizes the lone pair of electrons on the nitrogen atom and makes it less available for proton donation. In contrast, piperidine has a more localized lone pair on the nitrogen atom, making it more readily available for proton donation, thus making piperidine a stronger base than pyridine.
Aniline is less basic than ammonia because the nitrogen lone pair on aniline is partially delocalized into the benzene ring, making it less available to accept a proton. Ammonia, on the other hand, has a more localized lone pair on nitrogen, which is more readily available for protonation.
Because the electron withdrawing resonance efect caused by the nitro group on the structure, it makes the electrons pair on the nitrogen less available, if the electron pair is less available it's less basic
Yes aniline is heavier than water.Answer:Aniline i slightly denser than water. An equal volume of aniline will have about 2% more mass than water.