no. moles = mass / molecular weight
molecular weight = 64.06
mass = 28.4
28.4 / 64.06 =
.4433moles sulphur
For this you need the atomic mass of S. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.4 mole S × (32.1 grams) = 77.0 grams S
You will need to convert to moles, and then atoms. Here is the equation: (5.10 grams over one) times (1 mol S over 32.06 g S) times (6.022 X 10 23 atoms over 1 mol S) the last part of the equation is read six point zero two two times ten to the twenty third.
At STP one mole of any gas occupies 22.4 L. The equation for the reaction is CaCO3(S) - -> CaO (s) + CO2 (g). Moles of CO2 in 93.0 L is 93/22.4 = 4.15 moles, the ratio of moles of CaCO3 and CO2 is 1:1, therefore 4.15 moles of CaCO3 will be required. 1 mole of CaCO3 is equal to 100.087 g/mol. Therefore, 4 .15 moles will have 415.2 grams.
there are 4.5 moles
delta H=[2(-791.4kJ)]-o.oo-o.oo delta H=-1582.8 kJ/mol (6.44g S x 1mole S x 2 moles SO3) / (32.06g S x 1mole S)=0.200moles SO3 (0.200mole x -791.4) / (2 moles) = -79.14
Potassium has atomic number 39.1.Amount of K in 284g sample = 284/39.1 = 7.26molThere are 7.26 moles of potassium in a 284g sample.
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3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
6,5 grams of sulfur S are equal to 0,203 moles.
6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
Here are 0,2 moles sulfur.
7.71 grams sulfur (1 mole S/32.07 grams) = 0.2404 moles of sulfur
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300 g sulfur is equivalent to 9,36 moles.
Depict moles eg: Fe2O3(s) + 3CO(g)--> 2Fe(s) + 3CO2(g) 1 mole of Fe2O3 4 moles of CO 2 moles of Fe 3 moles of CO2
The mass of 2,65 Ag moles is 285,85 g.
Hydrogen reacts with sulfur in the proportions dictated by this equation:H2 + S --> H2S. The reactants are in a 1:1 proportion with each other, so 1.72 moles of hydrogen will react with 1.72 moles of sulfur.