no. moles = mass / molecular weight
molecular weight = 64.06
mass = 28.4
28.4 / 64.06 =
.4433moles sulphur
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
You will need to convert to moles, and then atoms. Here is the equation: (5.10 grams over one) times (1 mol S over 32.06 g S) times (6.022 X 10 23 atoms over 1 mol S) the last part of the equation is read six point zero two two times ten to the twenty third.
To find the mole fraction of ethanol, you first calculate the total moles of the solution, which is 3.00 + 5.00 = 8.00 moles. Then, you divide the moles of ethanol by the total moles of the solution: 3.00 moles / 8.00 moles = 0.375. So, the mole fraction of ethanol in the solution is 0.375.
To find the number of moles of hydrogen in 3.5 moles of (NH4)2CO3, first identify the stoichiometry of the compound. In (NH4)2CO3, there are two moles of hydrogen per mole of compound. Therefore, in 3.5 moles of (NH4)2CO3, there would be 2 * 3.5 = 7 moles of hydrogen.
Potassium has atomic number 39.1.Amount of K in 284g sample = 284/39.1 = 7.26molThere are 7.26 moles of potassium in a 284g sample.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
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6,5 grams of sulfur S are equal to 0,203 moles.
6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
To determine the number of moles of sulfur (S) present in 7.71g of S, you should first find the molar mass of sulfur, use it to convert the grams of sulfur to moles. Sulfur has a molar mass of approximately 32.06 g/mol, so the number of moles of S present in 7.71g is 7.71g / 32.06 g/mol = 0.24 moles of S.
Hydrogen reacts with sulfur in the proportions dictated by this equation:H2 + S --> H2S. The reactants are in a 1:1 proportion with each other, so 1.72 moles of hydrogen will react with 1.72 moles of sulfur.
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Depict moles eg: Fe2O3(s) + 3CO(g)--> 2Fe(s) + 3CO2(g) 1 mole of Fe2O3 4 moles of CO 2 moles of Fe 3 moles of CO2
The mass of 2,65 Ag moles is 285,85 g.
After 3 moles of S have reacted, 3 moles of F2 will also have reacted since the reaction ratio is 1:1 based on the balanced chemical equation. This leaves 6 moles of F2 remaining (9 moles initially - 3 moles reacted).
To find the number of moles of S in 22.9 g of C6H10S, you need to first calculate the molar mass of C6H10S, which is 126.23 g/mol. Then, divide the given mass by the molar mass to find the number of moles. For S in C6H10S, the molar mass contribution is 32.06 g/mol, so 22.9 g is equivalent to 0.717 moles of S.