The formula of the compound shows that each molecule contains 4 total atoms, 3 of oxygen and one of sulfur. Therefore, the number of atoms in 1.14 moles is 4 X 1.14 X Avogadro's Number or about 2.75 X 1024 atoms.
I assume you mean atoms. 2.4 X 10^24 atoms SO3 ( 1mol SO3/6.022 X 10^23 ) = 3.985 mol
In each sulfur trioxide molecule there is one sulfur atom and three oxygen atoms, giving a total of four atoms. In 1.14 moles of sulfur trioxide, there would be 1.14 x 6.02 x 10^23 = 6.87 x 10^23 molecules. Accordingly, there would be 4 x 6.87 x 10^23 = 2.75 x 10^24 atoms in total.
To determine the percent sulfur by mass in SO3, you need to consider the molar mass of each element. In SO3, there is one sulfur atom with a molar mass of 32.06 g/mol and three oxygen atoms with a molar mass of 16.00 g/mol each. Calculate the total molar mass of SO3, then determine the mass contributed by sulfur in that total mass to find the percent sulfur by mass.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
The molar mass of SO3 is 80.06 g/mol, with oxygen contributing 48.00 g/mol, which is 60% of the total molar mass. Therefore, the approximate percent by mass of oxygen in SO3 is 60%.
The molar mass of SO3 is 80.06 g/mol. Oxygen makes up three of these four atoms, so the oxygen's molecular weight in SO3 is 48 g/mol (3 x 16). Therefore, the percent by weight of oxygen in SO3 is (48 g/mol / 80.06 g/mol) x 100% = 59.97%.
I assume you mean atoms. 2.4 X 10^24 atoms SO3 ( 1mol SO3/6.022 X 10^23 ) = 3.985 mol
In each sulfur trioxide molecule there is one sulfur atom and three oxygen atoms, giving a total of four atoms. In 1.14 moles of sulfur trioxide, there would be 1.14 x 6.02 x 10^23 = 6.87 x 10^23 molecules. Accordingly, there would be 4 x 6.87 x 10^23 = 2.75 x 10^24 atoms in total.
To determine the percent sulfur by mass in SO3, you need to consider the molar mass of each element. In SO3, there is one sulfur atom with a molar mass of 32.06 g/mol and three oxygen atoms with a molar mass of 16.00 g/mol each. Calculate the total molar mass of SO3, then determine the mass contributed by sulfur in that total mass to find the percent sulfur by mass.
2S + 3O2 >> 2SO3 8.0 grams O2 (1 mole O2/32 grams)(2 mole SO3/3 mole O2) = 0.1666 ( 0.17 moles SO3 ) and also, 0.1666 moles SO3 (80.07 grams/1 mole SO3) = 13.34 ( 13 grams SO3 ) if needed.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
The molar mass of SO3 is 80.06 g/mol, with oxygen contributing 48.00 g/mol, which is 60% of the total molar mass. Therefore, the approximate percent by mass of oxygen in SO3 is 60%.
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
There are 3.79 times 6.02*1023 molecules in 3.79 mol CCl4 with 3.79 times 5 (=4+1) atoms in 3.79 mol CCl4So multplying all this gives you the answer:3.79 * 6.02*1023 * 5 = 114*1023 = 1.14*1025 atoms in 3.79 mole(of any compound with 5 atoms in one molecule)
There are approximately 4.65 x 10^22 atoms in 0.0077 mol of carbon.
The answer is 18,061.1023 atoms.
48,177 134 32.1023 atoms