I assume you mean atoms.
2.4 X 10^24 atoms SO3 ( 1mol SO3/6.022 X 10^23 ) = 3.985 mol
How_many_moles_of_each_atom_are_in_2.00moles_of_sulphur_trioxide
There are 6.87 x 10^23 atoms in 1.14 moles of SO3 since 1 mole of SO3 contains 6.02 x 10^23 molecules and each molecule contains 4 atoms (1 sulfur atom and 3 oxygen atoms).
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The formula of the compound shows that each molecule contains 4 total atoms, 3 of oxygen and one of sulfur. Therefore, the number of atoms in 1.14 moles is 4 X 1.14 X Avogadro's Number or about 2.75 X 1024 atoms.
In each sulfur trioxide molecule there is one sulfur atom and three oxygen atoms, giving a total of four atoms. In 1.14 moles of sulfur trioxide, there would be 1.14 x 6.02 x 10^23 = 6.87 x 10^23 molecules. Accordingly, there would be 4 x 6.87 x 10^23 = 2.75 x 10^24 atoms in total.
How_many_moles_of_each_atom_are_in_2.00moles_of_sulphur_trioxide
There are 6.87 x 10^23 atoms in 1.14 moles of SO3 since 1 mole of SO3 contains 6.02 x 10^23 molecules and each molecule contains 4 atoms (1 sulfur atom and 3 oxygen atoms).
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
The balanced chemical equation for the reaction is 2SO2 + O2 -> 2SO3. This means that for every 1 mole of O2 consumed, 2 moles of SO3 are produced. Therefore, 1.32 moles of O2 would produce 2.64 moles of SO3.
To find the number of moles, you first need to calculate the molar mass of SO3, which is 80.06 g/mol. Then, you can use the formula: moles = mass / molar mass. Thus, for 20g of SO3, you would have 20g / 80.06 g/mol = 0.25 moles of SO3.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The formula of the compound shows that each molecule contains 4 total atoms, 3 of oxygen and one of sulfur. Therefore, the number of atoms in 1.14 moles is 4 X 1.14 X Avogadro's Number or about 2.75 X 1024 atoms.
To find the mass of 1.12 moles of SO3, you first need to determine the molar mass of SO3. Sulfur has a molar mass of approximately 32.06 g/mol, and each oxygen atom has a molar mass of approximately 16.00 g/mol. Adding these together gives a molar mass of SO3 as approximately 80.06 g/mol. Multiplying the molar mass by the number of moles gives the mass of 1.12 moles of SO3 as approximately 89.67 grams.
Since oxygen is diatomic it requires 2 moles of oxygen.
In each sulfur trioxide molecule there is one sulfur atom and three oxygen atoms, giving a total of four atoms. In 1.14 moles of sulfur trioxide, there would be 1.14 x 6.02 x 10^23 = 6.87 x 10^23 molecules. Accordingly, there would be 4 x 6.87 x 10^23 = 2.75 x 10^24 atoms in total.
How many cups are in 5555555555 gallons
The balanced equation for the reaction is: 2SO2 + O2 -> 2SO3. Therefore, 1 mole of O2 is needed to react with 2 moles of SO2 to form 2 moles of SO3. So for 200 moles of SO2, you would need 100 moles of O2. At STP, 1 mole of any gas occupies 22.4 L, so the volume of O2 needed would be 2240 L (100 moles x 22.4 L).