By definition, each mole contains Avogadro's Number of molecules. Therefore, 3 moles contain about 3 X 6.022 X 1023 or about 1.807 X 1024. If the number of moles is not considered to be an exact integer, this should be written as 2 X 1024 in order to avoid unjustifiably many significant digits.
By balancing the chemical equation for the formation of ammonia (NH3) from nitrogen gas (N2) and hydrogen gas (H2), we have: N2 + 3H2 → 2NH3 This means that for every 1 molecule of N2 and 3 molecules of H2, we get 2 molecules of NH3. Therefore, from 2 molecules of N2 and 6 molecules of H2, we can form 4 molecules of NH3.
1 mol of any substance contains 6.02 x 1023 constituent particles. This is the avogadro constant. So in 10 moles of NH3, there would be 10 x 6.02 x 1023 = 6.02 x 1024 NH3 molecules.
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen gas (O2) is 4 NH3 + 5 O2 → 4 NO + 6 H2O. This means that 5 moles of O2 are needed to react with 4 moles of NH3. With 10.0 moles of NH3, you would need 12.5 moles of O2 (10.0 moles NH3 x 5 moles O2 / 4 moles NH3).
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------
By balancing the chemical equation for the formation of ammonia (NH3) from nitrogen gas (N2) and hydrogen gas (H2), we have: N2 + 3H2 → 2NH3 This means that for every 1 molecule of N2 and 3 molecules of H2, we get 2 molecules of NH3. Therefore, from 2 molecules of N2 and 6 molecules of H2, we can form 4 molecules of NH3.
To find the number of molecules produced, first calculate the number of moles of H2 using its molar mass. Then, use the balanced chemical equation to relate the number of moles of H2 to NH3. Finally, convert the moles of NH3 to molecules using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
1 mol of any substance contains 6.02 x 1023 constituent particles. This is the avogadro constant. So in 10 moles of NH3, there would be 10 x 6.02 x 1023 = 6.02 x 1024 NH3 molecules.
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen gas (O2) is 4 NH3 + 5 O2 → 4 NO + 6 H2O. This means that 5 moles of O2 are needed to react with 4 moles of NH3. With 10.0 moles of NH3, you would need 12.5 moles of O2 (10.0 moles NH3 x 5 moles O2 / 4 moles NH3).
Since ammonia has a chemical formula of NH3, it contains one mole of nitrogen and three moles of hydrogen per mole of ammonia. Therefore, 3 moles of ammonia contain 3 moles of nitrogen and 9 moles of hydrogen atoms.
The coefficient (in this case a 2) indicates the number of moles or molecules of the compound. So, 2NH3 means there are 2 moles or 2 molecules of ammonia (NH3).
To find the mass in grams of 1.20x10^25 molecules of ammonia (NH3), you first calculate the molar mass of NH3 (17.031 g/mol). Then, divide the given number of molecules by Avogadro's number (6.022x10^23 molecules/mol) to find the number of moles, and finally, multiply the number of moles by the molar mass to get the mass in grams, which will be approximately 4.08x10^2 grams.
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3