For this you need the atomic (molecular) mass of NaCN. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NaCN= 49.0 grams
2.55 grams NaCN / (49.0 grams) = .0520 moles NaCN
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
.73 moles
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
234 grams :)
1
23.3772 grams are there in four tenths moles of sodium chloride
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
.73 moles
55.0 moles of sodium are equal to 1 264,44 g.
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
234 grams :)
0,40 moles of sodium chloride contain 23,376 g.
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22.98977 grams.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
Quite a few! 5.13 kilograms sodium (1000 grams/1 kg)(1 mole Na/22.99 grams) = 223 moles of sodium =================
The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.