Since 1 mole is (6.022×1023 molecules)/(mol), so 9.02 x 1023 molecules would be 1.4978... mol
http://en.wikipedia.org/wiki/Chlorine 1 mol of chlorine (Cl2) weighs (2*35.45 =)70,90 grams 134,5 grams of chlorine is (134,5/70,9 =) 1,897 mol of chlorinegas. 1,897 * 6,02 * 10^23 = 1,142 * 10^24 molecules of Cl2
9.02*1023 (molecules) divided by 6.022*1023 (molecules per mole) = 1.5 moles of ANY thing
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
You cannot produce any Iodine from chlorine, because chlorine (Cl2, gas) is an element, hence it does not contain any Iodine (I2, solid with purple vapor). However when 8.00 moles Cl2 react with excess (>16) moles potassium Iodide (KI) then also 8.00 moles of Iodine are produced, not FROM but BY MEANS OF chlorine. Cl2 + 2KI --> 2 KCl + I2
Chlorine gas is Cl2If you have 4.37 x 1018 atoms, you will have half that number of chlorine molecules.4.37 x 1018 atoms of Cl x 0.5 molecules of Cl2 / atoms of Cl = 2.20 x 1018 molecules of Cl2There are 6.02 x 1023 'things' in a mole.2.20 x 1018 molecules of Cl ÷ 6.02 x 1023 molecules / mole = 3.65 x 10-6 mole of Cl2.
23 moles of oxygen contain 138,509.10e23 molecules.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
Since chlorine gas is a diatomic molecule (Cl2), one mole of chlorine gas contains two moles of chlorine atoms. Therefore, 6.00 moles of chlorine atoms would be equivalent to 3.00 moles of chlorine gas.
The given number is 299 x1021=2.99 x 1023 one mole has 6.022 x 1023 molecules. Therefore, no. of moles= 2.99 x 1023/6.022 x 1023 = .496 moles
To find the number of moles of NCl₃ containing 2.55 x 10²⁴ chlorine atoms, we first note that each molecule of NCl₃ contains 3 chlorine atoms. Therefore, the number of NCl₃ molecules can be calculated by dividing the number of chlorine atoms by 3: [ \frac{2.55 \times 10^{24}}{3} = 8.50 \times 10^{23} \text{ molecules of NCl}_3. ] Next, to convert molecules to moles, we use Avogadro's number (6.022 x 10²³ molecules/mol): [ \frac{8.50 \times 10^{23}}{6.022 \times 10^{23}} \approx 1.41 \text{ moles of NCl}_3. ] Thus, there are approximately 1.41 moles of NCl₃ in 2.55 x 10²⁴ chlorine atoms.
6,022140857.1023 molecules---------------------------------------------1 mole2.1022 molecules--------------------------------------------------------------x molex = 0,033 moles
9 moles of bromine contain 54,2.10e23 molecules.
http://en.wikipedia.org/wiki/Chlorine 1 mol of chlorine (Cl2) weighs (2*35.45 =)70,90 grams 134,5 grams of chlorine is (134,5/70,9 =) 1,897 mol of chlorinegas. 1,897 * 6,02 * 10^23 = 1,142 * 10^24 molecules of Cl2
9.02*1023 (molecules) divided by 6.022*1023 (molecules per mole) = 1.5 moles of ANY thing
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
One mole is 6.022 × 1023 (or 602,200,000,000,000,000,000,000) bits of anything. You have 18.9 moles. Thus: 18.9 × (6.022 × 1023) = 1.138158 × 1025 (or 11,381,580,000,000,000,000,000,000) molecules Cl2.