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Because the formula shows that each molecule of ethanol contains 2 atoms of carbon, 6* atoms of hydrogen, and 1 atom of oxygen, the gram molecular mass of one mole of ethanol is the sum of twice the gram Atomic Mass of carbon, 6 times the gram atomic mass of hydrogen, and the atomic mass of oxygen: 46.07. Therefore, 39.2 grams of ethanol constitutes 39.2/46.07 or 0.851 mole, to the justified number of significant digits.
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The subscript 5 immediately after the first appearance of the atomic symbol for hydrogen in the formula, plus the implied subscript 1 of the second appearance of the atomic symbol for hydrogen in the formula.
What else can I help you with?
How many moles of carbon are in 1.271 grams of ethanol?
For this you need the atomic (molecular) mass of C2H5OH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. C2H5OH= 46.1 grams1.271 grams C2H5OH / (46.1 grams) = .0276 moles C2H5OH
What is the number of moles in 508 g of ethanol?
To find the number of moles in 508g of ethanol (C2H5OH), first calculate the molar mass of ethanol: 2(12.01) + 6(1.01) + 1(16.00) = 46.08 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 508g / 46.08 g/mol ≈ 11 moles.
What is the total sample size (in grams) for a sample of ethanol (CH3CH2OH) which contains 3.36 g of oxygen?
9.675 g Since oxygen has an average atomic weight of 15.999 g/mol that would make it 0.21 moles of oxygen. Ethanol has one atom of oxygen per molecule so that means 0.21 moles of ethanol. Since ethanol has a molecular weight of 46.07 g/mole, 0.21 moles of ethanol would have a mass of 9.675 g.
What is the mole fraction of ethanol in a solution of 3.00 moles of ethanol and 5.00 moles of water?
To find the mole fraction of ethanol, you first calculate the total moles of the solution, which is 3.00 + 5.00 = 8.00 moles. Then, you divide the moles of ethanol by the total moles of the solution: 3.00 moles / 8.00 moles = 0.375. So, the mole fraction of ethanol in the solution is 0.375.
How many molecules of ethanol are contained in a 19.6 mL sample of ethanol?
The density of ethanol is 0.789 g/mL. So 19.6 mL of ethanol weighs 0.789 g/mL * 19.6 mL = 15.464 g. The molar mass of ethanol is 2*12.011 + 6*1.008 + 15.999 = 46.069 g/mol. So, in 15.464 grams, there are 15.464 g / 46.069 g/mol = 0.33567 moles In one mole, there are 6.022*1023 molecules, so we have: 0.33567 moles * 6.022*1023 molecules/mole= 2.0214*1023 molecules. Using correct significant digits, that gives: 2.02*1023 molecules (or particles).
How many moles are represented by 11.5g of c2H5oh?
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
What is the mole fraction of ethanol C2H5OH in an aqueous soloution that is 50.0 ethanol by mass?
To find the mole fraction of ethanol (C2H5OH), you first need to calculate the moles of ethanol in the solution. Then, calculate the total moles of all components in the solution. Finally, divide the moles of ethanol by the total moles to get the mole fraction. In this case, since the solution is 50% ethanol by mass, you can assume 50 g of the solution to make calculations simpler.
How many moles of carbon are in 1.271 grams of ethanol?
For this you need the atomic (molecular) mass of C2H5OH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. C2H5OH= 46.1 grams1.271 grams C2H5OH / (46.1 grams) = .0276 moles C2H5OH
How many moles in 11.5 g of C2H5OH?
1.5 - your welcome
What is the mass of 0.5623 moles of ethanol ch3ch2oh?
To calculate the mass of 0.5623 moles of ethanol (C2H5OH), you need to use the molecular weight of ethanol, which is approximately 46.07 g/mol. Multiply the number of moles by the molecular weight to get the mass: 0.5623 moles x 46.07 g/mol ≈ 25.89 grams. Therefore, the mass of 0.5623 moles of ethanol is approximately 25.89 grams.
How many moles of a substance are present in a sample if the sample weighs 5 grams and the molar mass of the substance is 30 g/mol (Dalton to moles conversion)?
To find the number of moles in a sample, divide the sample's weight by the molar mass of the substance. In this case, if the sample weighs 5 grams and the molar mass is 30 g/mol, the number of moles present in the sample would be 0.167 moles.
How many moles of CO2 are produced from each mole of C2H5OH completely burned?
In each mole of ethanol there are two moles of carbon atoms. One mole of carbon atoms is required to form one mole of carbon dioxide, so two moles will form two moles. Thus each mole of ethanol completely combusted will form two moles of carbon dioxide.
How many grams of oxygen will react with 2 mole of ethanol?
The balanced chemical equation for the reaction of ethanol with oxygen to form carbon dioxide and water is C2H5OH + 3O2 -> 2CO2 + 3H2O. From this equation, we can see that 3 moles of oxygen are needed to react with 1 mole of ethanol. Therefore, 2 moles of ethanol will require 6 moles of oxygen to react. To find the grams of oxygen, you can multiply the moles of oxygen by its molar mass (32 g/mol).
What is the number of moles in 508 g of ethanol?
To find the number of moles in 508g of ethanol (C2H5OH), first calculate the molar mass of ethanol: 2(12.01) + 6(1.01) + 1(16.00) = 46.08 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 508g / 46.08 g/mol ≈ 11 moles.
What is the molarity of methanol and ethanol?
The molarity of methanol (CH3OH) and ethanol (C2H5OH) depends on the concentration of each substance in a given solution. To calculate the molarity, you need to know the amount of the solute (methanol or ethanol) in moles and the volume of the solution in liters. The formula for molarity is moles of solute divided by liters of solution.
What is the total sample size (in grams) for a sample of ethanol (CH3CH2OH) which contains 3.36 g of oxygen?
9.675 g Since oxygen has an average atomic weight of 15.999 g/mol that would make it 0.21 moles of oxygen. Ethanol has one atom of oxygen per molecule so that means 0.21 moles of ethanol. Since ethanol has a molecular weight of 46.07 g/mole, 0.21 moles of ethanol would have a mass of 9.675 g.
What are the mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume-The density of water is 1.00g per mL and that of ethanol is 0.789 grams per mL?
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
