2x(6.02x10^23)
-APEX
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The mass of 2.000 mol of oxygen atoms is 32.00 grams.
At STP (Standard Temperature and Pressure), the volume occupied by 1 mol of any gas is 22.4 L. Thus, 0.25 mol of oxygen gas occupies (0.25 mol) * (22.4 L/mol) = 5.6 L in the mixture. The total volume of the gas mixture can be found as the sum of the individual volumes of oxygen, nitrogen, and carbon dioxide. Then, the mole fraction of oxygen gas is the moles of oxygen gas divided by the total moles of all gases in the mixture.
In one molecule of diphosphorus pentoxide (P2O5), there are 5 oxygen atoms. So, in 5.00 mol of P2O5, there would be 5.00 mol * 5 = 25.00 moles of oxygen atoms.
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms
See the Related Question linked the the left of this answer: = How do you solve an Ideal Gas Law problem? = Note that STP is standard temperature and pressure. Standard pressure is 1 atm, and standard temperature is 0 °C, which is 273.15 Kelvin.
To calculate the number of oxygen atoms in 16.0 pounds of oxygen, first convert 16.0 pounds to grams (1 pound ≈ 453.592 grams). Then, calculate the number of moles of oxygen using the molar mass of oxygen (16.00 g/mol). Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of oxygen atoms.
There are 1 mol of oxygen atoms in 1 mol of CO2. Therefore, in 0.5 mol of CO2, there are 0.5 mol of oxygen atoms. Number of molecules = 0.5*6.022 *10^23 ≈ 3.011 *10^23 molecules
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
Mass of Hydrogen gas:- 2g/mol Mass of Oxygen gas :- 32g/mol Therefore, Oxygen gas is more heavier
The answer is 18,061.1023 atoms.
The total moles of gas in the mixture is 0.25 + 1.50 = 1.75 mol. The mole fraction of oxygen gas is the moles of oxygen gas divided by the total moles, so 0.25 mol / 1.75 mol = 0.143. Therefore, the mole fraction of oxygen gas in the mixture is 0.143.
firstly, you cannot have 1.20105 molecules, it is physically impossible to have a non-integer number of molecules. But I will assume you mean 1.20105 mol. Simply multiply the number of mols of oxygen atoms by avagadros number so 1.20105 mol of n205 = 1.20105*5mol of oxygen atoms. 1.20105 x 5 x 6.022e-23 is your answer
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
In 4.42 mol of H2O2, there are 26.52 moles of oxygen atoms. This is because each molecule of H2O2 contains two oxygen atoms.
After the reaction is complete, all of the calcium will react with 3.165 mol (since calcium and oxygen react in a 1:1 ratio) of the oxygen gas. This means that there will be 4.00 mol - 3.165 mol = 0.835 mol of oxygen gas left over.
To find the number of oxygen atoms in 3.120 grams, we need to first calculate the number of moles using the molar mass of oxygen gas. The molar mass of oxygen gas is 32 g/mol. So, 3.120 grams is equal to 0.0975 moles. Each mole of oxygen gas contains 2 oxygen atoms, so there are 0.195 moles of oxygen atoms in 3.120 grams. Finally, using Avogadro's number (6.022 x 10^23), we find that 1.17 x 10^23 oxygen atoms are present in 3.120 grams of oxygen gas.
There are 4 oxygen atoms in 1 molecule of SO2. Therefore, in 1.25 mol of SO2, there would be 5 moles of oxygen atoms (4 * 1.25 = 5). Using Avogadro's number, we can determine that there are 3.01 x 10^24 oxygen atoms in 1.25 mol of SO2.