The molar mass of an element corresponds to the Atomic Mass of the element (found on the Periodic Table). The atomic mass of Sodium-Na is 22.990 g, which is also the molar mass of Na. So for 1 mole of Na, there are 22.990 grams of Na. If we had 3 moles of Na, then we would simply multiply the molar mass by 3.
One mole of sodium is 22.99 grams. The atomic mass of an element is how many grams one mole weighs.
2.35 mol Na X (grams Na / 1 mol Na) = grams Na
the element's amu on your periodic table is the amount of grams in one mole of that element.
The mass in grams of one mole of any element is numerically equal to its atomic weight. The atomic weight of sodium is 22.98976928 so the mass in grams of one mole is 23 grams
1M NaOH contains 40 grams of NaOH
23g
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
3.00 grams NaHCO3 (1 mole/84.008 grams) = 0.0357 moles of sodium bicarbonate
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
72.6 grams of sodium (1 mole Na/22.99 grams)(6.022 X 10^23/1 mole Na) = 1.90 X 10^24 atoms of sodium
28.75 grams sodium (1 mole Na/22.99 grams)(6.022 X 1023/1 mole Na) = 7.531 X 1023 atoms of sodium ------------------------------------------
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Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
3.00 grams NaHCO3 (1 mole/84.008 grams) = 0.0357 moles of sodium bicarbonate
Not much! 2980 atoms sodium [1 mole Na/6.022 X 1023 (atoms)][22.99 grams/1 mole Na] = 1.138 X 10 -19 grams sodium ====================
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
72.6 grams of sodium (1 mole Na/22.99 grams)(6.022 X 10^23/1 mole Na) = 1.90 X 10^24 atoms of sodium
28.75 grams sodium (1 mole Na/22.99 grams)(6.022 X 1023/1 mole Na) = 7.531 X 1023 atoms of sodium ------------------------------------------
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
1.8066 x 1024 sodium ions
Balanced equation. 4Na + O2 ->2Na2O 14.6 grams Na (1 mole Na/22.99 grams)(1 mole O2/4 mole Na)(32.0 grams/1 mole O2) = 5.08 grams oxygen gas needed --------------------------------------------
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================