This is a supersaturated solution.
The solubility of silver nitrate in water at 20 degrees Celsius is 11.1 g/5.0 g or 2.22 g/g. This means that for every gram of water, 2.22 grams of silver nitrate can dissolve at this temperature.
To make 1 kg of silver nitrate (AgNO3), you would need approximately 169.87 grams of silver (Ag) along with other reactants such as nitric acid. This is based on the molar mass of silver nitrate, which is 169.87 g/mol.
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
To find how many grams of silver nitrate can be produced, first determine the limiting reactant. Calculate the moles of silver nitrate and calcium chloride in the given volumes and concentrations. The reactant that produces fewer moles of silver nitrate will be the limiting reactant. Then use stoichiometry to find the amount of silver nitrate that can be produced from the limiting reactant.
To find the limiting reactant, we need to determine how many grams of silver chloride can be produced from each reactant and compare the results. Calculate the amount of silver chloride that can be produced from 10.0 g of silver nitrate. Calculate the amount of silver chloride that can be produced from 15.0 g of barium chloride. The reactant that produces the lesser amount of silver chloride will be the limiting reactant.
The solubility of silver nitrate in water at 20 degrees Celsius is 11.1 g/5.0 g or 2.22 g/g. This means that for every gram of water, 2.22 grams of silver nitrate can dissolve at this temperature.
You need 145,337 g silver nitrate.
You need 26,49 g silver nitrate.
The mass of silver nitrate is 30,6 g.
9.11 g
To make 1 kg of silver nitrate (AgNO3), you would need approximately 169.87 grams of silver (Ag) along with other reactants such as nitric acid. This is based on the molar mass of silver nitrate, which is 169.87 g/mol.
The answer is 95,34 g.
20 grams of silver nitrate would produce an equivalent amount of silver chloride if all the silver nitrate is converted. The molar ratio of AgNO3 to AgCl is 1:1, so 20 grams of AgNO3 would produce 20 grams of AgCl.
530,3 g potassium iodide are needed.
When silver nitrate reacts with sodium chloride, silver chloride is formed according to the equation: AgNO3 + NaCl -> AgCl + NaNO3. The molar ratio of silver nitrate to silver chloride is 1:1. Therefore, 100 g of silver nitrate will produce 143.32 g of silver chloride.
The answer is 14,35 g AgCl.
The solubility of poassium nitrate in water at 20 oC is 616 g/L.