This is a supersaturated solution.
635 grams silver 99.99% to produce 1 kg of silver nitrate walha kamel chemical technician Tunisia
63.4g
8.44g
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
431.5 grams
You need 145,337 g silver nitrate.
You need 26,49 g silver nitrate.
The mass of silver nitrate is 30,6 g.
9.11 g
58.9g
635 grams silver 99.99% to produce 1 kg of silver nitrate walha kamel chemical technician Tunisia
The answer is 95,34 g.
The percentage of silver nitrate by weight is 100[5.48/(5.48 + 25.0)] = 18.0 %, to the justified number of significant digits.
530,3 g potassium iodide are needed.
The solubility of poassium nitrate in water at 20 oC is 616 g/L.
63.4g