Using the formula : K= compound per ml of organic solvent/ compound per ml of water.
You have 4 mg left in the aqueous layer, hence, 31 mg in the organic layer. Converting mg to g you have: (.031g / 5ml) / (.004g/ 10ml) = 15.5.
normality of BA in water / square root of normality of BA in benzene = 0.028 to 0.035
square root of normality of BA in benzene /normality of BA in water = 32 to 39
(4mg/10ml)/(31mg/5ml) = .0645 = Kp
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preparation of m-nitro benzoic acid from benzene
I can't find a number, but I found this: Benzoic acid is slightly soluble in water, soluble in ethanol, very slightly soluble in benzene and acetone. (see link on the left under Web Links) This implies not very much benzoic acid will dissolve in benzene. This other site (the MSDS for benzoic acid) says this: SOLVENT SOLUBILITY: Soluble in alcohol, ether, benzene, chloroform, acetone, carbon disulfide, oil of turpentine, carbon tetrachloride, fixed and volatile oils; slightly soluble in petroleum ether, hexane. This does make it sound fairly soluble! Hard to say which is right. This can easily be determined by experiment however!
Benzene is a non polar solvent with low dielectric constant, whereas water is a polar solvent with high dielectric constant. So water can reduce the interaction between benzoic acid molecules there by preventing them from dimerizing, which cannot be done by benzene
Toluene + HNO3/H2SO4 --> p-nitrotoluene (para directed nitration) p-nitrotoluene + Zn/HCl --> p-aminotoluene (changing NO2 to NH2 by reduction) p-aminotoluene +Br2 --> bromination ortho to NH2 Remove NH2 via diazonium salt and decomposition with 1) HONO (which is NaNO2+HCl), 2) H3PO2 for the final product.
dipole-dipole attraction with Ethyl acetate molecules would overcome the H-bond attraction between Benzoic Acid molecules due to ratio of the non-polar to polar portion of the benzoic acid molecules to its polar
To determine the partition coefficient of Benzoic Acid between Benzene and water the solubility of benzoic acid is required. The partition can then be determined by calculation.
benzene after oxidation convert into benzoic acid. zahra khan.
Benzoic acid will give brisk effervescence on reacting with sodium bicarbonate.
preparation of m-nitro benzoic acid from benzene
Not sure what you mean... If you mean 'how is benzene used for the Grignard synthesis of Benzoic Acid,' then the answer is, bromobenzene (C6H5Br) is turned into phenyl Grignard (C6H5MgBr) by the addition of Magnesium in ether, and then dry ice (solid CO2) is added to the reaction mixture to make Benzoate (C6H5COO-), which is the conjugate base of Benzoic Acid. That has got to help you somehow.
I can't find a number, but I found this: Benzoic acid is slightly soluble in water, soluble in ethanol, very slightly soluble in benzene and acetone. (see link on the left under Web Links) This implies not very much benzoic acid will dissolve in benzene. This other site (the MSDS for benzoic acid) says this: SOLVENT SOLUBILITY: Soluble in alcohol, ether, benzene, chloroform, acetone, carbon disulfide, oil of turpentine, carbon tetrachloride, fixed and volatile oils; slightly soluble in petroleum ether, hexane. This does make it sound fairly soluble! Hard to say which is right. This can easily be determined by experiment however!
Benzoic acid is soluble in water, as are all acids, by definition. An acid is a chemical which, when dissolved in water, increases the concentration of H+ ions.
Benzoic acid is unsaturated because it has double- double carbon bonds and due to resonance those bonds can be easily move around , that's what makes benzoic acid unique. All compounds containing a benzene ring are actually unsaturated.
Any molecule containing carbon that is NOT either carbon monoxide, carbon dioxide, or any allotrope of elemental carbon is considered to be organic. Seeing as benzoic acid is a carboxylic acid created by a benzene ring, it most definetely is organic
Benzene is a non polar solvent with low dielectric constant, whereas water is a polar solvent with high dielectric constant. So water can reduce the interaction between benzoic acid molecules there by preventing them from dimerizing, which cannot be done by benzene
Benzoic acid is the stronger acid compared to ethanoic acid. However, ethanoic acid is more corrosive and will burn skin etc more than benzoic acid. Corrosivity/burn potential are not the same as acid strength. This is due to the delocalisation of the lone pair of electrons on the oxygen atom into the benzene, increasing the polarity of the -OH bond and thus makes the cleaving of the H+ ion easier. The delocalisation of electrons into the benzene ring also stabilises the carboxylate ion. Therefore the position of equilibrium lies more to the right and this shows that benzoic is a more acidic acid. The simplified version is that a benzene ring is electron withdrawing and a methyl group is electron releasing. The electron withdrawing power makes the releasing of the H+ ion easier.
it melts