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An atom of fluorine has the greatest attraction among all atoms for electrons; therefore, no other atom can extract an electron from a fluorine atom, as would be required for the fluorine to have a positive oxidation state.

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10y ago
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1mo ago

Fluorine has the highest electronegativity of all elements, meaning it strongly attracts electrons. This results in fluorine almost always having an oxidation state of -1 in compounds, as it gains one electron to achieve a stable electron configuration. It is energetically unfavorable for fluorine to lose electrons and thus have a positive oxidation state.

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Q: Why is fluorine oxidation state never positive?
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Related questions

Which of these elements has an oxidation state of -1?

Fluorine typically has an oxidation state of -1.


Why is the oxidation state of fluorine never positive?

Fluorine's electronegativity is very high, meaning it readily gains electrons rather than loses them to achieve a more stable electron configuration. This behavior leads to a high tendency for fluorine to have a negative oxidation state in compounds.


What compound has the atom with the highest oxidation number?

The compound with the highest oxidation number would be an oxide of fluorine, such as OF₂. In this compound, the oxidation state of fluorine is +2, which is the highest oxidation state observed for fluorine.


What is the Oxidation states for nitrogen hydrogen and fluorine in nh4f?

In NH4F, nitrogen has an oxidation state of -3, hydrogen has an oxidation state of +1, and fluorine has an oxidation state of -1.


What is the oxidation stateof F in HOF?

The oxidation state of F in HOF (hydrogen monofluoride) is -1. Hydrogen is typically assigned an oxidation state of +1, leaving the fluorine with an oxidation state of -1.


Which halogen naturally exists in positive oxidation no?

Fluorine is the only halogen that does not naturally exist in any positive oxidation state. The other halogens - chlorine, bromine, iodine, and astatine - can exist in various positive oxidation states, though they are less common in nature compared to their negative oxidation states.


What is the oxidation states of the elements in FClO4?

FClO4 is the name of Fluorine perchlorate.Here Chlorine is in +7 oxidation state, Fluorine is in -1 oxidation state, 3 atoms of Oxygen (that are double bonded to Chlorine) are in -2 oxidation state, and the forth Oxygen atom (which is connected to Fluorine and Chlorine) is in 0 oxidation state.So, total charge = 7(of Chlorine) -1(of Fluorine) -(2 * 3)(of 3 Oxygen) +0(of Fourth Oxygen) = 0


How can you calculate the oxidation state of fluorine in O2F2?

To calculate the oxidation state of fluorine in a compound, you can use the general rule that oxygen usually has an oxidation state of -2. In O2F2, since there are two oxygen atoms with a total oxidation state of -4, the two fluorine atoms must have a total oxidation state that balances it out to zero. This means each fluorine atom has an oxidation state of +2.


What is the oxidation numbers for the compound HF?

In the compound HF, the oxidation number of hydrogen (H) is +1 and the oxidation number of fluorine (F) is -1. This is because fluorine is more electronegative than hydrogen, so it takes on a -1 oxidation state while hydrogen takes on a +1 oxidation state.


Is there any compound in which fluorine has 1 oxidation state?

HF


What is the oxidation number for fluorine in a compound?

The oxidation number of fluorine in a compound is typically -1. Fluorine is highly electronegative, so it tends to gain an electron to achieve a full outer shell, giving it a -1 oxidation state.


Why is fluorine's oxidation number is always negative?

Fluorine is highly electronegative, meaning it has a strong attraction for electrons. As a result, when fluorine forms compounds, it tends to gain an electron to achieve a full outer shell, leading to an oxidation state of -1. This consistent oxidation state of -1 for fluorine arises from its strong tendency to gain electrons in chemical reactions.