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To find the effective resistance of resistors connected in parallel, you can use the following formula:

1/Reff = 1/R1 + 1/R2 + 1/R3 + ...

In this case, we have three resistors connected in parallel: a 120-ohm resistor, a 60-ohm resistor, and a 40-ohm resistor.

1/Reff = 1/120 + 1/60 + 1/40

To simplify the equation, we need to find a common denominator:

1/Reff = (1/120) + (2/120) + (3/120)

1/Reff = 6/120

Now, let's invert both sides of the equation:

Reff = 120/6

Reff = 20 ohms

Therefore, the effective resistance of the three resistors connected in parallel is 20 ohms.

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Paul Marios

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11mo ago
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11y ago

The effective resistance of those three resistors in parallel is 20 ohms.

And it makes no difference what the power source is, or whether they're even

connected to a power source at all. As soon as those three resistors are in parallel,

their effective resistance is 20 ohms immediately, even if they're still in the drawer.

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14y ago

Reff = R1*R2 / (R1+R2)

if you follow this for all three, you will end up with 20 ohms.

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林咸宇

Lvl 1
1y ago
1/R=1/R1+1/R2+1/R3; Then, R=20ohms

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8y ago

120 v across 120 ohms = 1 amp

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Q: A 120 ohm resistor a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source What is the effective resistance of the three resistors?
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