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The effective resistance of those three resistors in parallel is 20 ohms.

And it makes no difference what the power source is, or whether they're even

connected to a power source at all. As soon as those three resistors are in parallel,

their effective resistance is 20 ohms immediately, even if they're still in the drawer.

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Is it possible to connect a group of resistors of value R in such a way that the equivalent resistance is less than R?

Yes. When resistors are connected in "parallel" (all the left ends connected together and all the right ends connected together) the effective resistance is always less then the smallest resistor in the group. For example If you connected a 2 ohm in parallel with a 4 ohm the effective resistance is 1.33 ohm. To your question; if you connect N equal resistors R in parallel the effective resistance would be R/N . The formula for calculating effective resistance R of a group R1, R2, R3, ... in parallel is: 1/R = 1/R1 + 1/R2 + 1/R3 + .... Note; write the right side as a single fraction by getting a common denomenator then invert to get R.


If a 1 ohm resistor is parallel with a 100 ohm resister what's the total resistance?

If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.


What is the resistance between any two of the corners if Three 3 ohm resistors are connected such that it make triangle.?

2 ohms. It is like connecting two 3 ohm resistors in series and then these two series resistors are connected in parallel with third 3 ohm resistor in parallel


What will happen to the other resistor if the number of resistor decreases?

the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.


How do you find resistance in a parallel circuit?

resistance inparallel decrease in value proportionally two resistance can be calculated as R1XR2/SUM OF R1+R2. many values can be calculated as a fraction 1/r+1/r2+1/3 ....and take the total sum reciprocal

Related Questions

What is the difference between connecting resistors in parallel and in series?

When resistors are connected in series, the total resistance is the sum of the individual resistances. When resistors are connected in parallel, the total resistance is less than the smallest individual resistance.


What are the differences between resistors connected in parallel and resistors connected in series, and how do these configurations affect the overall resistance in a circuit?

Resistors connected in parallel have the same voltage across them, while resistors connected in series have the same current passing through them. In a parallel configuration, the total resistance decreases as more resistors are added, while in a series configuration, the total resistance increases.


How are parallel resistors connected?

If you need a resistor of a certain value, and you have no resistors with small enough values,you can create the one you need by connecting several of those you have in parallel.The effective net resistance of resistors in parallel is always less than the smallest individual.And the more resistors you add in parallel, the smaller the net effective resistance becomes.


A 120 ohm resistor a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source. What is the effective resistance of the three resistors?

The effective resistance of those three resistors in parallel is 20 ohms. And it makes no difference what the power source is, or whether they're even connected to a power source at all. As soon as those three resistors are in parallel, their effective resistance is 20 ohms immediately, even if they're still in the drawer.


How many 40 Ω resistors connected in parallel are required to carry 1.5 A on a 12.0 V line?

The required resistance is 12/1.5 = 8Ω.Five 40Ω resistors in parallel have an effective resistance of 8Ω.


Three equal resistors connected in series across a voltage source dissipate a power of 10W what sould be the power desipated if same resistors are connected in parallel?

If three equal resistors are connected in parallel, the equivalent resistance will be one-third of the resistance in series. This lower resistance will result in a higher current flowing through the resistors when connected in parallel compared to when they are in series. Therefore, the power dissipated by the resistors in parallel will be greater than 10W.


When 2 resistors are connected in parallel r1r2 are?

Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.


How do you connect several resistances if you want to decrease in total resistance without reducing the number of resistors?

The resistors should be connected in parallel .


How to measure resistance of series combination?

When connected in series, the overall effective resistance of a bunch of individual resistors is the sum of the individual resistances. It's always more than the resistance of any individual. When connected in parallel, the reciprocal of the overall resistance of a bunch of individual resistors is the sum of the reciprocals of the individual resistances. It's always less than the resistance of any individual. When two resistors are connected in parallel, the overall effective resistance of the pair is (the product of the two individual resistances) divided by (the sum of the two individual resistances). It's always less than the smaller individual resistance.


Is it possible to connect a group of resistors of value R in such a way that the equivalent resistance is less than R?

Yes. When resistors are connected in "parallel" (all the left ends connected together and all the right ends connected together) the effective resistance is always less then the smallest resistor in the group. For example If you connected a 2 ohm in parallel with a 4 ohm the effective resistance is 1.33 ohm. To your question; if you connect N equal resistors R in parallel the effective resistance would be R/N . The formula for calculating effective resistance R of a group R1, R2, R3, ... in parallel is: 1/R = 1/R1 + 1/R2 + 1/R3 + .... Note; write the right side as a single fraction by getting a common denomenator then invert to get R.


Why is resistance less when resistors are join in parallel?

What do you mean? In a parallel circuit, the combined (or effective) resistance is less than any individual resistance.


How does electricity react to resistances in parallel and in series?

Resistances in series act just as if they were one single resistor. The value of the single resistor is the sum of the individual resistors connected in series ... Ra + Rb + Rc etc. When several resistors are in series, the effective total is greater than the biggest one. Resistance in parallel act just as if they were one single resistor. The reciprocal of the value of the single resistor is the sum of the reciprocals of the individual resistors connected in parallel ... Total effective resistance = 1 divided by (1/Ra + 1/Rb + 1/Rc + etc.) When several resistors are in parallel, the effective total is less than the smallest one. Once you figure out the effective value of the series- or parallel-combination of many resistors, you handle them as if they were one single resistor, and you can work with the voltage and current: Current through any resistance = (Voltage across it) divided by (its resistance).