Power, P, is current, I, times voltage, E. (P = IE)
Not knowing one of voltage, E, or current, I, you can apply ohm's law ...
E = IR or I = E/R
... and come up with variations ...
P = I2R
P = E2/R
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
The power dissipated in a voltage divider circuit is given by the formula P = V^2/R, where V is the voltage across the resistor and R is the resistance of the resistor. If the resistance in the voltage divider circuit is increased, the power dissipated in the circuit will decrease. This is because as resistance increases, the current flowing through the circuit decreases, leading to less power being dissipated as heat in the resistors.
Take your pick:P = V x I (Power = Voltage x Current)or:P = V2 / R (Power = Voltage2 / Resistance)or:P = I2 *R (Power = Current2 x Resistance)(the last two equations come from combining the ohms law equation R=V/I with the power equation P=VxI)In the question above you have resistance and current therefore:P = I2 *R = 0.0052 x 8.2k = 0.0052 x 8200 = 0.205W = 205mW
Power dissipated is always Volts times Amps. W= V*I because of ohm's law, V=I*R, you can substitute either the voltage or amperage with the other value; W= V^2/R or W= I^2*R.
The power dissipated by a resistance 'R' carrying a current 'I' is [ I2R ]. The power is dissipated as heat, and you can see from [ I2R ] that for a given current, it's directly proportional to 'R'.
The i squared r formula is used in electrical engineering to calculate the power dissipated as heat in a circuit due to the resistance of the components and the current flowing through them.
That's not always the case. One formula for power dissipated is:P = IRSo, a higher resistance means that more power is dissipated - if the current is the same. The reason for this is precisely that resistance is related to the conversion of electrical energy into heat.However, if you put a higher resistance across a specific voltage, you'll get less power dissipation, not more, since less current will flow at a higher resistance.
The formula for calculating the power dissipated in a resistor, known as the i2r power, is P I2 R, where P is the power in watts, I is the current in amperes, and R is the resistance in ohms.
No, power is not directly proportional to resistance. The power dissipated in a circuit is given by P = I^2 * R, where I is the current flowing through the circuit and R is the resistance. This means that power is proportional to the square of the current but linearly proportional to resistance.
The relationship between power (P), current (i), and resistance (r) in an electrical circuit is described by the formula P i2 r. This means that power is directly proportional to the square of the current and the resistance in the circuit.
P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.
Power = I2 R = (0.02)2 x (1,000) = 0.4 watt
Power dissipated in a resistance = E2/R = (100)2/100 = 100 watts.
The power dissipated in a resistor can be calculated using the formula P = I^2 * R, where P is power, I is current, and R is resistance. Plugging in the values given, we get P = (0.02 A)^2 * 300 ohms = 0.012 watts. Therefore, the power dissipated in the 300-ohm resistor with a current of 20 mA is 0.012 watts.
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
7.0w/4 = 1.75w