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Power, P, is current, I, times voltage, E. (P = IE)
Not knowing one of voltage, E, or current, I, you can apply ohm's law ...
E = IR or I = E/R
... and come up with variations ...
P = I2R
P = E2/R
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How Determine the power dissipated by the resistor?
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
What is the power dissipated a resistor with a current of 0.02 amps and a resistance of 1000 ohms?
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
What is the power dissipated by an 8.2k ohm resistor if a current of 0.005 amps is passing through the resistor?
Take your pick:P = V x I (Power = Voltage x Current)or:P = V2 / R (Power = Voltage2 / Resistance)or:P = I2 *R (Power = Current2 x Resistance)(the last two equations come from combining the ohms law equation R=V/I with the power equation P=VxI)In the question above you have resistance and current therefore:P = I2 *R = 0.0052 x 8.2k = 0.0052 x 8200 = 0.205W = 205mW
What is the power dissipated in the Ohm resistor?
Power dissipated is always Volts times Amps. W= V*I because of ohm's law, V=I*R, you can substitute either the voltage or amperage with the other value; W= V^2/R or W= I^2*R.
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
Why does the heating effect of an electric current depends on the electrical resistance of a conductor?
The power dissipated by a resistance 'R' carrying a current 'I' is [ I2R ]. The power is dissipated as heat, and you can see from [ I2R ] that for a given current, it's directly proportional to 'R'.
Why does largest R dissipate more power?
That's not always the case. One formula for power dissipated is:P = IRSo, a higher resistance means that more power is dissipated - if the current is the same. The reason for this is precisely that resistance is related to the conversion of electrical energy into heat.However, if you put a higher resistance across a specific voltage, you'll get less power dissipation, not more, since less current will flow at a higher resistance.
What is the power dissipated by a resistor with a current of 0.02 A and a resistance of 1000 ohms?
Power = I2 R = (0.02)2 x (1,000) = 0.4 watt
A 100 ohm resistor is placed across a 100v power source what is the power?
Power dissipated in a resistance = E2/R = (100)2/100 = 100 watts.
How Determine the power dissipated by the resistor?
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
The average power dissipated by a resistor connected to a sinusoidal emf is 7.0W. What is P avg if the resistance R is doubled?
7.0w/4 = 1.75w
Examples of resistive heating?
In a toaster, the house current from the outlet passes through a wire with some resistance. Household electricity is supplied at a nominal 117 volts AC. If 'R' is the resistance of the wire in the toaster, then the power (heat) dissipated by the wire is E2/R = (117)2/R watts of heat. Notice that as long as the voltage remains constant, MORE resistive heat is dissipated from a SMALLER resistance.
What is the power dissipated by a resistor with a current of 2 amps and a resistance of 1000 ohms?
I = 2A R = 1000Ω Power Dissipated P = I2R = (2A)2(1000Ω) = 4000W Voltage across resistor V = IR = (2A)(1000Ω) = 2000V
What is the difference between P I2R or P V 2R?
The formula P = I^2R relates power (P), current (I), and resistance (R), indicating the power dissipated in a resistor. On the other hand, the formula P = V^2/R relates power (P), voltage (V), and resistance (R), representing the power dissipated across a resistor. The former formula deals with power in terms of current, while the latter formula expresses power in terms of voltage.
What is power dissipation in resistance?
The power P dissipated by a resistor will leave the resistor in the form of thermal energy (heat). It will get hot due to the fact that the material it is made of opposes current flow, and when current is forced through it by a voltage source, it gets hot in response. Resistance R could be thought of as "electrical friction" in many cases. Resistance is measured in ohms, voltage V in volts and current I in amperes (amps). The power in watts dissipated by a resistor with the value R will be the square of the current through it times its resistance. P=I2R The power in watts dissipated by a resistor with the value R will be the square of the voltage drop across it divided by its resistance. P=V2/R Because E means energy we take V for voltage. The power in watts dissipated by a resistor with the value R will be the voltage drop across it times the current flow through it. P=IV All three statements are true, and they all say the same thing. The mathematician might say that the variable P is being expressed in terms of the variables I, V and R. As all the statements are true, it can be said that P=I2R=V2/R=IV.
What is the power dissipated a resistor with a current of 0.02 amps and a resistance of 1000 ohms?
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
A 14point1 V battery is connected to a 142 resistor Neglecting the internal resistance of the battery calculate the power dissipated in the resistor Answer in units of W?
In a DC circuit, the power dissipated by a resistance is (voltage across it)2 divided by 'R'.P = E2/R = (14.1)2 / 142 = 198.81/142 = 1.4 watts(rounded)
